.bashrc unexpected end of file

Question

I've searched and found several answers but I didn't succeed in altering mine.

Operating system : Mac OS X

My .bashrc content

# Before other PATHs...
PATH=${PATH}:/usr/local/share/python

alias la='ls -la'

function find_cpp_filepath_with_string { find $1 -name "*.cpp" -type f -exec  grep -l $2 {} \;}

#export -f find_cpp_filepath_with_string

else
    echo "WARNING: Can't find virtualenvwrapper.sh"
fi

The troublesome line is the following

function find_cpp_filepath_with_string { find $1 -name "*.cpp" -type f -exec  grep -l $2 {} \;}

after trying source ~/.bashrc the result is :

line 21: syntax error: unexpected end of file

The .bashrc is really complete here? – Idriss Neumann Dec 01 '13 at 12:10 — Idriss Neumann, Dec 01 '13 at 12:10
I removed some more path variables that were commented out – serj Dec 01 '13 at 12:15 — serj, Dec 01 '13 at 12:15

score 4 · Accepted Answer · answered Dec 01 '13 at 12:14

4

You're correct when you say that the troublesome line is the following. You are missing a semicolon. Say:

function find_cpp_filepath_with_string { find $1 -name "*.cpp" -type f -exec grep -l $2 {} \; ; }
                ^
                |-----  You need to add a semicolon here!

The first semicolon is required to denote the end of -exec for the find command. The second one is required following the command group.

answered Dec 01 '13 at 12:14

devnull

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I was so close, tried ;; instead of ; ;. Thank you very much ! – serj Dec 01 '13 at 13:28

.bashrc unexpected end of file

1 Answers1