Too many arguments for function call operator overload

Question

I'm attempting to overload the () operator to accept a long, that code is below.

struct print{
    void operator()(long x){
        printf("Number: %d\n",x);
    }
};

However when I write this:

print p();
long l = 10;
p(l);

The compiler yells at me saying "error : too many arguments in function call" on the line that corresponds to p(l);

Why isn't this working, did I overload the () operator correctly?

yes you can overload the () it is called a functor or function object...heres a link to a youtube vid that gives a code example of a functor http://www.youtube.com/watch?v=4BQz0ZXMye4&feature=youtu.be — Josh Engelsma, Dec 03 '13 at 03:02

Jesse Good · Accepted Answer · 2013-12-03T03:09:14.893

6

You hit the most vexing parse. Change print p(); to print p;.

print p() is a declaration of a function named p which returns a print object.

Also, in C++, an empty parameter list means a function taking no arguments (same as (void)), which is why the compiler complains: " too many arguments in function call".

edited Dec 03 '13 at 03:09

answered Dec 03 '13 at 03:02

Jesse Good

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Jesse, you're good. Pun intended. :-D – Fiddling Bits Dec 03 '13 at 03:12

Too many arguments for function call operator overload

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