Confuse about creating the object

Question

I am just starting out with Java. But I had a big puzzle when I am in the first chapter. It says that we have to "initialize" the handle when we are creating one, like String s = "asdf", and later it says we have create a new object for the string s again, String s = new String("asdf");.

I think the string s already has an object (asdf) in the "initialization", but why we still have to re-create it again(if I am understanding it right)?

Hope someone can explain this more to me, in book it is just skipped.

Read this : http://stackoverflow.com/questions/3297867/difference-between-string-object-and-string-literal — Ant's, Dec 03 '13 at 11:16
Read this http://stackoverflow.com/questions/3052442/what-is-the-difference-between-text-and-new-stringtext-in-java — Neha Choudhary, Dec 03 '13 at 11:22

Maroun · Accepted Answer · 2013-12-03T11:22:12.797

2

String str1 = "asdf";               //This is a String literal
String str1 = new String("asdf");   //This is a String object

String objects are on the heap, whereas the literals are on the common pool for string literals.

Noe that if you do String s = "asdf"; and then String s = new String("asdf"); you'll get a compilation error for redeclaring s.

See the JLS for further information.

edited Dec 03 '13 at 11:22

answered Dec 03 '13 at 11:17

Maroun

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Alright. So a String _object_ needs to create a new space of the memory to str1, however a String _literal_ is like quoting (or linking?) an already-established memory space (not sure if I put it in this way right) to it? – user3061156 Dec 04 '13 at 01:27

Confuse about creating the object

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