Check if object/array is empty

Question

I'm trying to check if the following is empty or not.

{"players":""}

I have a function that gets that from an api/site and.. well, heres the code.

function getPlayers($server) {
    // Fetches content from url and json_decodes it
    $playersList = getUrl('http://api.iamphoenix.me/list/?server_ip=' . $server);
    // Attempting to check if it's empty.
    if ($playersList != "") {
        // convert list of comma-separated names into array
        $players = explode(',', $playersList->players);
        foreach ($players as $player) {
            echo '<img title="'.$player.'" src="https://minotar.net/avatar/'.$player.'/32">';
        }
    } else {
        return 'empty';
    }
}

However, using !=, empty(), or isset(), I still get an empty string, example:

https://minotar.net/avatar//32

Where it should be..

https://minotar.net/avatar/Notch/32

When it's empty, I'd like it to just return 'empty'.

I'm not sure what I'm doing wrong. Any ideas?

Have you tried `if (!empty($player)) {` within the `foreach`? — Dave Chen, Dec 04 '13 at 05:11
I think the function getUrl returns an object of data not array of data. — HTTP, Dec 04 '13 at 05:25
possible duplicate of [How to check that an object is empty in PHP](http://stackoverflow.com/questions/9412126/how-to-check-that-an-object-is-empty-in-php) — kenorb, Mar 04 '15 at 22:18

score 1 · Answer 1 · answered Dec 04 '13 at 05:20

In pure php you can check the url segments like

$_SERVER['REQUEST_URI_PATH'] = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
$segments = explode('/', $_SERVER['REQUEST_URI_PATH']);

if($segments[2] == '') { 
}
//or
if(empty($segments[2])) { 
}

//or do your condition

if you are using codeigniter you might say

if(empty($this->uri->segment(2)))

But be sure you loaded the url helper

Hope I understand your question!

Punitha · Answer 2 · 2013-12-04T05:24:18.863

0

try this

if (isset($playersList) && is_array($playersList) && !empty($playersList)) {

    // convert list of comma-separated names into array
    $players = explode(',', $playersList->players);
    foreach ($players as $player) {
        echo '<img title="'.$player.'" src="https://minotar.net/avatar/'.$player.'/32">';
    }
} else {
    return 'empty';
}

edited Dec 04 '13 at 05:24

answered Dec 04 '13 at 05:18

Punitha

152
1
12

score 0 · Answer 3 · answered Dec 04 '13 at 05:18

0

You should do this;

print_r($playersList);

just after you set it to see what it actually is. My guess is that you are not getting what you suspect from the getURL call.

answered Dec 04 '13 at 05:18

Nick M

1,647
13
17

score 0 · Answer 4 · answered Dec 04 '13 at 05:21

0

Add one more equals sign to take type comparison into account as well

if ($playerList !== '')

answered Dec 04 '13 at 05:21

Rejinderi

11,694
2
31
40

score 0 · Accepted Answer · answered Dec 04 '13 at 05:34

Since you were able to have some output, see my changes in the codes.

function getPlayers($server) {
    // Fetches content from url and json_decodes it
    $playersList = getUrl('http://api.iamphoenix.me/list/?server_ip=' . $server);
    // Attempting to check if it's empty.
    if ($playersList != "") {
        // convert list of comma-separated names into array
        $players = explode(',', $playersList->players);
        // check conversion
        if(is_array($players) && !empty($players){
            foreach ($players as $player) {
                echo '<img title="'.$player.'" src="https://minotar.net/avatar/'.$player.'/32">';
            }
        } else {
            return 'empty';
        }
    } else {
        return 'empty';
    }
}

Check if object/array is empty

5 Answers5