code is invalid under python 2.6 but fine in 2.7

Question

can someone help me translate some python 2.7 syntax to python 2.6 please (kinda stuck on 2.6 due to redhat dependencies)

so i have a simple function to construct a tree:

def tree(): return defaultdict(tree)

and of course i would like to display the tree in some way. under python 2.7 i can use:

$ /usr/bin/python2.7
Python 2.7.2 (default, Oct 17 2012, 03:00:49)
[GCC 4.4.6 [TWW]] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def dicts(t): return {k: dicts(t[k]) for k in t}
...
>>>

all good... but under 2.6 i get the following error:

$ /usr/bin/python
Python 2.6.6 (r266:84292, Sep  4 2013, 07:46:00)
[GCC 4.4.7 20120313 (Red Hat 4.4.7-3)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> def dicts(t): return {k: dicts(t[k]) for k in t}
  File "<stdin>", line 1
    def dicts(t): return {k: dicts(t[k]) for k in t}
                                           ^
SyntaxError: invalid syntax

how can i rewrite the code:

def dicts(t): return {k: dicts(t[k]) for k in t}

so that i can use it under python 2.6?

score 6 · Accepted Answer · answered Dec 05 '13 at 02:24

6

You have to replace the dict comprehension with the dict() being passed a generator expression. ie.

def dicts(t): return dict((k, dicts(t[k])) for k in t)

answered Dec 05 '13 at 02:24

John La Rooy

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score 0 · Answer 2 · answered Dec 05 '13 at 02:55

0

def dicts(t):
    d = {}
    for k in t:
        d[k] = dicts(t[k])
    return d

answered Dec 05 '13 at 02:55

hpaulj

221,503
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code is invalid under python 2.6 but fine in 2.7

2 Answers2