PHP, session error

Question

I have a problem with my check.php for a login system I am building, the error reads

Parse error: syntax error, unexpected '{' in /home/ob219/public_html/logsystem/check.php on line 3

My code is

    <?php
session_start();
if (!isset($_SESSION['user_logged_in']) || $_SESSION['user_logged_in'] !== true {
header('Location: login.php');
}
?>

I have tried to remove the brackets {} but then it has a problem with header

possible duplicate of [Parse Error: syntax error: unexpected '{'](http://stackoverflow.com/q/7059753) — mario, Dec 06 '13 at 18:40

score 1 · Accepted Answer · answered Dec 06 '13 at 18:39

1

You're missing your closing parenthesis:

if (!isset($_SESSION['user_logged_in']) || $_SESSION['user_logged_in'] !== true {

should be

if (!isset($_SESSION['user_logged_in']) || $_SESSION['user_logged_in'] !== true) {

answered Dec 06 '13 at 18:39

John Conde

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score 1 · Answer 2 · answered Dec 06 '13 at 18:39

1

Try this:

<?php
    session_start();
    if (!isset($_SESSION['user_logged_in']) || $_SESSION['user_logged_in'] !== true)
    {
        header('Location: login.php');
    }
?>

answered Dec 06 '13 at 18:39

sensorario

20,262
30
97
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PHP, session error

2 Answers2