compare two arrays and show only the matching items Jquery

Question

var rundhalsArray = ["50237451_001", "50237451_100"];
var Array = ["50237451_001", "50237451_100", "50236765_001", "50236765_100"];

I have two arrays and would like to only display the items that match when comparing them so the result of the above would be:

var resultArray = ["50237451_001", "50237451_100"];

How's this different from your last question http://stackoverflow.com/questions/20522169/remove-set-of-items-from-an-array-jquery? — j08691, Dec 11 '13 at 18:26

score 2 · Answer 1 · answered Dec 11 '13 at 18:28

2

http://jsfiddle.net/kL69J/

This is how I would do it:

var array1 = ["a", "b", "c", "d", "e", "f"];
var array2 = ["a", "b", "c", "d", "e", "f", "g", "h", "i"];
var foo = [];

$.grep(array2, function(el) {

    if ($.inArray(el, array1) != -1) {
        foo.push(el);
    }

});


alert(" they have the same " + foo);

answered Dec 11 '13 at 18:28

Pedro Estrada

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Thank you very much for the useful snippet. Helped a lot @Pedro Estrada – Ana DEV Sep 14 '17 at 08:47

score 1 · Answer 2 · answered Dec 11 '13 at 18:35

JSFIDDLE DEMO

var rundhalsArray = ["50237451_001", "50237451_100"];
var arr = ["50237451_001", "50237451_100", "50236765_001", "50236765_100"];

var result = [];
$.map(rundhalsArray, function (val, i) {
    if ($.inArray(val, arr) > -1) {
        result.push(val);
    }
});
console.log(result);

compare two arrays and show only the matching items Jquery

2 Answers2