How to manipulate and assign parts of a MATLAB field - Comma-separated list assignment

Question

Consider the following MATLAB struct:

a(1).num=1; a(2).num=2; a(3).num=3;

The thing I want to do is to replace some of the elements of num with the old value minus a (scalar) number. For example, I would like to subtract 1 from a(2).num and a(3).num.

I already tried different ways:

a(2:3).num=a(2:3).num-1;


??? Error using ==> minus Too many input arguments.

Next try:

>>a(2:3).num=[a(2:3).num]-1;

??? Insufficient outputs from right hand side to satisfy comma separated list 
expansion on left hand side. Missing [] are the most likely cause.

And last:

>> [a(2:3).num]=[a(2:3).num]-1;

??? Error using ==> minus
Too many output arguments.

arrayfun couldn´t help either. Probably there is a quite easy answer to this question, but I couldn´t find any.

Related: http://stackoverflow.com/questions/2337126/how-do-i-do-multiple-assignment-in-matlab — Rody Oldenhuis, Dec 12 '13 at 14:21

score 2 · Accepted Answer · answered Dec 12 '13 at 14:17

Easiest is a two-line solution:

C = num2cell([a(2:3).num]-1);
[a(2:3).num] = C{:}

Nicest is to have a function like deal, but with a function applied to each argument:

function varargout = fcnDeal(varargin)

    %// (Copied from MATLAB's deal()

    if nargin==1,
        varargout = varargin(ones(1,nargout));
    else
        if nargout ~= nargin-1
            error('fcnDeal:narginNargoutMismatch',...
                'The number of outputs should match the number of inputs.')
        end
        %//...Except this part
        varargout = cellfun(varargin{1}, varargin(2:end), 'UniformOutput', false);
    end

end

Then what you want to do is just a matter of

[a(2:3).num] = fcnDeal(@(x)x-1, a(2:3).num)

Thank you for this elegant solution. I chose the first one, since i understand better what it does. — Paul Paulsen, Dec 12 '13 at 15:06

score 1 · Answer 2 · answered Dec 12 '13 at 14:22

1

You can manipulate them in the loop

index = [1,2] 
for i = index
a(i).num = a(i).num - 1;
end

answered Dec 12 '13 at 14:22

pezetem

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Thank you for your answer as well. I prefer the way without the loop as Rody suggested. – Paul Paulsen Dec 12 '13 at 15:07
@Paul: In akfaz' defense: if you type `edit num2cell`, you'll see that that is essentially a loop as well. Akfaz' solution might actually be slightly faster, since there is no function call, and error checking etc. is skipped. – Rody Oldenhuis Dec 12 '13 at 15:42
Thats interesting to know. Thanks! – Paul Paulsen Dec 12 '13 at 16:39

How to manipulate and assign parts of a MATLAB field - Comma-separated list assignment

2 Answers2