Rally python api - Adding a Tag to an entity?

Question

I wanted to use pyral to add tags to defects and I couldn't figure out how to do it

info = dict(test_id="ABC", platform="AAA")
tag1 = rally.create('Tag', dict(Name=info['test_id']))
tag2 = rally.create('Tag', dict(Name=info['platform']))

what's next ?

score 4 · Accepted Answer · edited May 23 '17 at 11:46

4

found an answer here: how to tag a defect using rally Javascript API

anyhow adding it to documentation might help:

tag1 = rally.create('Tag', dict(Name=info['test_id']))
tag2 = rally.create('Tag', dict(Name=info['platform']))

tags = [ dict(_ref=tag1.ref), dict(_ref=tag2.ref)]

defect = { "Tags" : tags }

edited May 23 '17 at 11:46

Community

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answered Dec 12 '13 at 21:54

Fruch

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5
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Thanks for posting this, you saved me a lot of time! – amcolosk Jul 11 '14 at 13:54
Glad to be of service :) – Fruch Sep 14 '14 at 07:44
Note that to add a tag in an existing item you can use `rally.addCollectionItems(workitem, [tag])` as mentionned in this answer https://stackoverflow.com/a/49826345/1603480 – Jean-Francois T. Dec 12 '18 at 09:28

Rally python api - Adding a Tag to an entity?

1 Answers1