1

input file not work :

form.php

<form  action='process.php' method="post"  enctype="multipart/form-data" >
<input type='text' name='name' />
<input type='file' name='photo' />
<input type='submit' name='submit' />
</form>

process.php

if($_POST){


foreach($_POST as $key = > $value ){
   if($key!='submit')
    echo $key.'='.$value.'<br/>';
}


}

output:

name=name

?! who can solve this problem for input files. please helpppppp....

Daniel
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  • As a note, adding extra Ps onto 'help' doesn't make your question that more urgent/important/etc. Secondly, you do realize that file inputs are arrays themselves, right? – Daedalus Dec 12 '13 at 23:58
  • I don't speak/read whatever that is. Please try to communicate in english. – Daedalus Dec 13 '13 at 00:16
  • Thank you, The above code does not work for input files How I fixed form data without the need to write their name into the form I send them all like this, output should be : key=name /r/n key=photo – Daniel Dec 13 '13 at 00:28

3 Answers3

1
foreach($_POST as $keyPost => $valuePost){ echo '<br>'.$keyPost." => ".$valuePost; }
kampageddon
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0
$key = > $value

is not valid syntax. 

$key => $value

PHP should have told Syntax error, unexpected '=' and on which line

Popnoodles
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0

You need to use $_FILES instead of $_POST.

And since $_FILES will return an array you can't just echo $value; See: Print $_POST variable name along with value

Community
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galengodis
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