Extracting Phone number from a String

Question

How do I extract phone numbers from a long string using regex. Here a phone number is a simple 10 digit number, no formatting eg. 1234567890, 0000000000

Possible duplicate : Extracting phone number from string

But here the accepted answer, just matches numbers (single digit, double digit, etc.. & not necessarily 10 digit phone numbers)

possible duplicate of [Extracting phone number from string](http://stackoverflow.com/questions/7912779/extracting-phone-number-from-string) — Chris Chambers, Dec 13 '13 at 07:22
@ChrisChambers : I wrote this already in my question, and I also mentioned why none of the answers there solve the problem — user96546, Dec 13 '13 at 07:27
Could any one point out which part of the question is unclear so that I can frame it better. I guess so many answers wouldn't have come, if it were maliciously framed — user96546, Dec 13 '13 at 10:30

score 2 · Answer 1 · answered Dec 13 '13 at 07:14

2

To match exactly 10 digits use [0-9]{10}

answered Dec 13 '13 at 07:14

piet.t

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score 1 · Accepted Answer · answered Dec 13 '13 at 07:14

1

\\d{10}can be used for only 10 digits

But a mobile no does not starts with zero so, do this [1-9]\\d{9}

answered Dec 13 '13 at 07:14

AJ.

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Anirudha · Answer 3 · 2013-12-13T07:23:26.620

1

List<String> list= new ArrayList<String>();
Matcher m=Pattern.complie("\\d{10}").matcher(input);
while(m.find())
    list.add(m.group());

edited Dec 13 '13 at 07:23

answered Dec 13 '13 at 07:17

Anirudha

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score 1 · Answer 4 · answered Dec 13 '13 at 07:30

1

Try this regex for match 10 digit number

[0-9]{10}

enter image description here

    String mob = "1234567890";
    if(mob.matches("[0-9]{10}"))
        System.out.println("Valid");
    else
        System.out.println("InValid");

answered Dec 13 '13 at 07:30

Rakesh KR

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score 1 · Answer 5 · answered Dec 13 '13 at 07:56

1

     String mobileNo = "[0-9]"; 
    int counter=0; 
    Pattern pattern = Pattern.compile(mobileNo); 
    Matcher matcher = pattern.matcher(The String in which we have to find the number);
    while(matcher.find())
{
System.out.println("STart index is "+matcher.start());
System.out.println("End index is "+matcher.end());
System.out.println(matcher.group);
counter++;
}
if(counter==10)
{
System.out.println("Mobile no. found");
counter=0;
}

answered Dec 13 '13 at 07:56

Khay

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Whats with theses people who had put the question on hold , I got two things for you guys 1. If you cant understand a question it does not imply that the question is useless and you shld put it on hold, if u wanna know the question just look at the answers too and you'll be clear with question ,i'm sure you must be that much smart , MR PUTTING QUestions on HOLD. 2.And if you think its too easy or something like that ,it does not imply that that you should close the topic , cuz a problem is a problem nothing else , and this community is not only for the people from MIT ,or stanford . – Khay Dec 13 '13 at 08:36

Extracting Phone number from a String

5 Answers5