printing all email addresses of a string

Question

given an string containing one or more email addresses,how can I go about writing a function that prints all valid email addresses of the string. consider code below which can decide if the string is exactly an email address ,meaning it can not decide if a string contains an email address. How can I develop this code, so it will check if a string contains one or more email addresses and then print them ?

import re
def check(email):
      return re.match(r'[^@]+@[^@]+\.[^@]+', email) != None

score 2 · Accepted Answer · edited May 23 '17 at 11:57

2

Use re.findall:

emails = re.findall('[^@ ]+@[^@ ]+\.[^@ ]+', stringWithEmails)

Edit: Well, probably you'll need a better RE for matching e-mails, see this question, for example.

edited May 23 '17 at 11:57

Community

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answered Dec 13 '13 at 14:52

pvgoran

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You should probably exclude spaces too. – smeso Dec 13 '13 at 14:53
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@Ingo: Can you explain your statement? – smeso Dec 13 '13 at 15:01
@Faust because for example this: `"STOP-ESM.org" ` is a valid E-Mail address. – Ingo Dec 13 '13 at 15:03
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No, `info@stop-esm.org` is a valid email address. `"STOP-ESM.org" ` is a valid content for the `rcpt-to` header. They are slightly different things. – smeso Dec 13 '13 at 15:18

printing all email addresses of a string

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