28

I have a list of items that I want to fit in a space that is constrained vertically:

<ul>
    <li>One</li>
    <li>Two</li>
    <li>Three</li>
    <li>Four</li>
    <li>Five</li>
    <li>Six</li>
</ul>

Since I don't want the list to have more than a specific height, but I'm free to expan it horizontally, I want to divide the list into columns, like this:

One    Two     Three
Four   Five    Six

Or, alternatively (in my case order is not important)

One    Three   Five
Two    Four    Six

The css property column-count allows to break a list into columns, but it only accepts a fixed number of columns. I don't know the number of items I am going to have (it can go from 1 to more than 40), so if I set the number of columns to 3, any list with more than 6 items will be too high, and if there is only 4 items, then only the first column will have two items and it will look uneven.

So, ideally I would need a row-count property, but it doesn't exist. I guess I can do that in Javascript too but I'm looking for a CSS-only solution.

I tried something: float:left on every li puts the list in one row. To break it into two rows, I would need to not apply float:left to the N/2 element. I don't know how to do that.

I know also that I can do it by breaking it into multiple ul, each one with two li, and float:left them, but I would like to avoid messing the HTML for something entirely presentational.

Does someone has a solution for this problem?

Edit: I think I have not been clear in explaining my requirements. I want the list to be sorted into columns without knowing how many items I'm going to have, and so that I will always have two rows.

So for example with 7 items, I want to have:

One    Two     Three   Four
Five   Six     Seven

And with 3 items:

One    Two
Three  
Cyrille Ka
  • 15,328
  • 5
  • 38
  • 58

8 Answers8

17

Here is a simple way to do it using jquery. I know it is mentioned that a CSS way is needed, but this is just for future reference if anyone wants to refer to this question.

Get the number of LI items and divide it by the number of rows and set that value to column-count property.

Jquery

$(document).ready(function() {
var numitems =  $("#myList li").length;

$("ul#myList").css("column-count",Math.round(numitems/2));
});

CSS

ul {
  width: 900px;
}
li {
width: 75px;
height: 75px;
margin-top: 10px;
margin-right: 10px;
display: inline-block;
}

HTML

<ul id="myList">
<li>One</li>
<li>Two</li>
<li>Three</li>
<li>Four</li>
<li>Five</li>
<li>Six</li>
<li>Seven</li>
<li>Eight</li>
<li>Nine</li>    
</ul>

Fiddle here

EDIT:

Same implementation using simple javascript.

var ul = document.getElementById("myList");
var li = ul.getElementsByTagName("li");
var numItems = li.length;

var css = document.createElement("style");
css.type = "text/css";
css.innerHTML = "ul { column-count: " + Math.round(numItems/2) + "; }";
document.body.appendChild(css);

You need to set the width of UL, because number of rows will depend on the width also even after setting the column-count. You can set it to 100% too, but then the number of rows will change based on the window size. To restrict the number of rows to 2, fixed width for UL may be required.

Poornima
  • 918
  • 5
  • 11
  • Thanks, I would prefer a CSS solution, but if that's not possible a simple JS will do :) – Cyrille Ka Dec 13 '13 at 16:03
  • I have updated my answer to use simple javascript instead of jquery, in case you decide to go ahead with this approach :) However I haven't tested the javascript approach very well, you might have to play with it a little bit to get it to work as expected. – Poornima Dec 13 '13 at 16:20
  • it only worked for me, when I converted the column-count number to a string, thanks! – igrossiter Oct 22 '14 at 18:19
10

You could set your li at 33% width and floating against each other, once there isn't enough room in a row they will be pushed down in rows of 3 of equal width.

ul li{
  width: 33%;
  float: left;
}
Afzaal Ahmad Zeeshan
  • 15,669
  • 12
  • 55
  • 103
user1620090
  • 499
  • 6
  • 19
5

I know this question is 7 years old but if anyone has similar problem today, then here's a solution using CSS Grid Layout (https://www.w3.org/TR/css-grid-1/)

ul {
    display: grid;
    grid-template-columns: repeat(3, 1fr);
}
mctl87
  • 351
  • 8
  • 16
2

Why not give it a max-width?

ul {
  max-width: somevalue; // which would last when the third item ends
}

Or, you can add class to them as

<ul>
    <li class="one">One</li>
    <li class="one">Two</li>
    <li class="one">Three</li>
    <li class="two">Four</li>
    <li class="two">Five</li>
    <li class="two">Six</li>
</ul>

Now CSS as:

.one {
  display: inline;
}

.two {
  display: inline;
}

The last thing of the padding is as

ul li {
  padding: somevalue;
} 

And for slicing:

ul {
  max-width: 200px; // to break the list
}

The good luck for you would be that you can first check the width of the list! And then slice it into two equal parts using JS, and then applying it.

If you want to get the CSS calucator, then use this:

width: calc(var1 + var2); // calc will do the math..

Here is the fiddle for this situation: http://jsfiddle.net/afzaal_ahmad_zeeshan/xN87Q/

Afzaal Ahmad Zeeshan
  • 15,669
  • 12
  • 55
  • 103
2

Here's an example using display: flex and flex-direction: row to change the ordering from columns to rows:

#list-1 {
  border: 3px solid red;
  columns: 2;
  column-gap: 5px;
  width: 200px;
}

#list-2 {
  border: 3px solid blue;
  columns: 2;
  display: flex;
  flex-direction: row;
  flex-wrap: wrap;
  height: auto; /* can change this */
  width: 200px;
}

#list-2 li {
  width: 100px;
  height: auto;
}
<ul id="list-1">
<li>a</li>
<li>b</li>
<li>c</li>
<li>d</li>
<li>e</li>
<li>f</li>
<li>g</li>
</ul>

<ul id="list-2">
<li>a</li>
<li>b</li>
<li>c</li>
<li>d</li>
<li>e</li>
<li>f</li>
<li>g</li>
</ul>
Ethan Ryan
  • 467
  • 10
  • 16
1

you can use

li:nth-child(even) 

li:nth-child(odd)

http://jsfiddle.net/nCmZT/

user3037493
  • 312
  • 2
  • 8
  • ahh... i see... to use this method the only way to guarantee only 2 rows is to give the ul a specific height, which you will have (per the question). in my fiddle, the UL does not have a height. – user3037493 Dec 13 '13 at 16:12
  • Setting the height of the ul does not change the fact there are still three rows: http://jsfiddle.net/nCmZT/2/ – Cyrille Ka Dec 13 '13 at 16:14
1

Source: Creating a two column Unordered List

Fiddle : Demo provided in the link

HMTL

<ul class="two-col-special">
    <li>First Category</li>
    <li>Second Category</li>
    <li>Third Category</li>
    <li>Fourth Category</li>
    <li>Fifth Category</li>
</ul>

CSS

.two-col-special {
    border: 1px dotted blue;
    overflow: auto;
    margin: 0;
    padding: 0;
}

.two-col-special li {
    display: inline-block;
    width: 45%;
    margin: 0;
    padding: 0;
    vertical-align: top; /* In case multi-word categories form two lines */
}
.two-col-special li:before {
    content: '+';
    padding: 5px;
    margin-right: 5px; /* you can tweak the gap */
    color: orange;
    background-color: white; /* in case you want a color... */
    display: inline-block;
}
Community
  • 1
  • 1
Amarnath Balasubramanian
  • 9,300
  • 8
  • 34
  • 62
0

I think the most easies and proper way {OL tag especially} would be:

<ul>
  <div class="row">
    <div class="col-6">
      <li>One</li>
      <li>Two</li>
      <li>Three</li>
    </div>
    <div class="col-6">
      <li>Four</li>
      <li>Five</li>
      <li>Six</li>
    </div>
   </div>
</ul>
M0ng0lZ
  • 11
  • 1