Correct syntax for using echo in PHP

Question

I run this code, and got this error:

 Parse error: syntax error, unexpected T_LNUMBER in C:\xampp\htdocs\Generate.php on line 5

What is the problem?

<?php
$satr=$_POST["satr"];
$soton=$_POST["soton"];
$bg=$_POST["bg"];
echo ("<table border="1" style="background-color:$bg">");
for($i=1;&i<=$satr;$i++)
{
    echo("<tr>");
    for($j=1;j<=$soton;$j++)
    {
        echo("<td>$soton</td>");
}
echo("</tr>");
}
echo("</table>");    

?>

@MikeBrant even with syntax highlighting he'd need to understand why its an error. — Toby Allen, Dec 13 '13 at 19:08
@TobyAllen The answer below give you that information. You have a quote escaping problem. — Mike Brant, Dec 13 '13 at 19:10
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. http://php.net/manual/en/function.echo.php — Dmitry Dubovitsky, Dec 16 '13 at 10:39

score 2 · Answer 1 · answered Dec 13 '13 at 19:20

    echo ("<table border='1' style='background-color:$bg'>");

    echo ('<table border="1" style="background-color:$bg">');

    echo "<table border=\"1\" style=\"background-color:$bg\">";

    echo '<table border="1" style="background-color:$bg">';

    echo "<table border='1' style='background-color:$bg'>";

score 1 · Answer 2 · edited May 23 '17 at 12:27

You dont need the parenthesis and you need to escape you inner double quotes

<?php
$satr=$_POST["satr"];
$soton=$_POST["soton"];
$bg=$_POST["bg"];
echo "<table border=\"1\" style=\"background-color:$bg\">";
for($i=1;&i<=$satr;$i++)
{
    echo "<tr>";
    for($j=1;j<=$soton;$j++)
    {
        echo "<td>$soton</td>";
    }
    echo "</tr>";
}
echo "</table>";
?>

Also look here What is the difference between single-quoted and double-quoted strings in PHP?

score 0 · Answer 3 · answered Dec 13 '13 at 19:02

0

Can you try this, you have used &i in for loop, you need to use $i

    $satr=$_POST["satr"];
    $soton=$_POST["soton"];
    $bg=$_POST["bg"];
    echo ("<table border='1' style='background-color:$bg'>");

    for($i=1;$i<=$satr;$i++)
    {
        echo("<tr>");
        for($j=1;j<=$soton;$j++)
        {
            echo("<td>$soton</td>");
        }

    echo("</tr>");
    }
    echo("</table>");

answered Dec 13 '13 at 19:02

Krish R

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What is the reason for Downvote Mr.Downvoter? – Krish R Dec 13 '13 at 19:13

score -2 · Answer 4 · edited Dec 13 '13 at 19:20

-2

You are not escaping the quotes in the string. You need to do something like this:

echo ("<table border=\"1\" style=\"background-color:$bg\">");

edited Dec 13 '13 at 19:20

ChrisF

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answered Dec 13 '13 at 19:00

PasteBT

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Correct syntax for using echo in PHP

4 Answers4