Comparing large numbers with javascript

Question

Possible Duplicate:
Subtracting long numbers in javascript

Can anyone tell me how to compare large numbers in javascript?

Something like

var sla = 1263293940000;
var resp = 1263296389700;

if(sla > resp)
{
    //do something
}

somewhat related: http://stackoverflow.com/questions/1653131/what-programming-language-will-enable-me-to-enter-a-very-long-number-without-conv/1653142#1653142 — jldupont, Jan 13 '10 at 15:12
Dup of: http://stackoverflow.com/questions/964139/huge-integer-javascript-library — Jason Orendorff, Jan 13 '10 at 15:51
Also very similar to http://stackoverflow.com/questions/2050111/subtracting-long-numbers-in-javascript which was just posted yesterday. — Jason Orendorff, Jan 13 '10 at 15:53

score 3 · Accepted Answer · answered Jan 13 '10 at 15:15

3

You might want to look into the BigInteger library.

answered Jan 13 '10 at 15:15

Alex Reisner

29,124
6
56
53

This function is also working for me. function numbersSort(lang, numbers) { numbers.sort(new Intl.Collator(lang,{numeric:true}).compare); return numbers; } console.log(numbersSort(this, ['12345678901234567890','1234567890123456789','123456789012345678'])); // expected output: Array ["123456789012345678", "1234567890123456789", "12345678901234567890"] – pathe.kiran Sep 06 '18 at 10:10

score 1 · Answer 2 · answered Nov 18 '12 at 11:13

1

return new Number(first)>new Number(second);

answered Nov 18 '12 at 11:13

vignesh

11
3

score 1 · Answer 3 · answered Jan 13 '10 at 15:21

Internally all javascript numbers are represented as double-precision floating point numbers. As you've discovered, this causes some rounding errors for very large numbers (and in other places). If you need more precision, you'll need to use a library like the one Alex posted.

score -4 · Answer 4 · answered Nov 18 '12 at 11:16

-4

return ('12345678901234568.13') <= ('12345678901234568.12');

answered Nov 18 '12 at 11:16

vignesh

11
3

Comparing large numbers with javascript

4 Answers4