Is there a way to slow down a variable++; function?

Question

I need a variable to count upwards but in increments of 2 seconds. Right now I'm simply using a ++; function, but as you know it's extremely fast.

Is there anything simple I can use to count at a slower pace?

`Thread.sleep( 2000 )` but it is not precise. You probably want something more like a `Timer` — clcto, Dec 14 '13 at 00:11
Agree with @clcto, You should read [Java: How to use Timer class to call a method, do something, reset timer, repeat?](http://stackoverflow.com/questions/9413656/java-how-to-use-timer-class-to-call-a-method-do-something-reset-timer-repeat), could be help to you. — Smit, Dec 14 '13 at 00:15

score 1 · Answer 1 · answered Dec 14 '13 at 00:11

1

Thread.sleep(2000);

This will make your program to wait for 2 seconds between this method call and whatever line of execution immediately follows this.

answered Dec 14 '13 at 00:11

nhgrif

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score 1 · Answer 2 · answered Dec 14 '13 at 00:16

public class Count implements Runnable{
  public void run(){
     for(int i=0;i<=6;i+=2){
         Thread.sleep(2000)//in milliseconds ...sleeping for 2 sec
         sysout(...);//print your value
       }
   }
}

Start it this way

Runnable r=new Count();
Thread t=new Thread(r);
t.start(); // start the  thread

What you doing is basicly making a thread and running with a delay.I hope you get a concept

score 0 · Answer 3 · answered Dec 14 '13 at 00:12

0

Yes, you can pause the execution for two seconds by using Thread.sleep(2000).

//Your code...
Thread.sleep(2000);
counter = counter + 2;
//Your code...

answered Dec 14 '13 at 00:12

SerotoninChase

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score 0 · Answer 4 · answered Dec 14 '13 at 00:13

This will print from 1 to 99, incrementing by 2 with a one second pause between increments.

public static void main(String[] args) {
  for (int i = 1; i < 100; i += 2) { // i = i + 2
    System.out.printf("i = %d\n", i); // print i = #
    try {
      Thread.sleep(2000); // two seconds.
    } catch (InterruptedException e) {
    }
  }
}

Is there a way to slow down a variable++; function?

4 Answers4