How to open a text file in python?

Question

I try to do the following,

file = open('test.txt', 'w+')
item = "hello"

file.write(item)
print(file)

When I run this program I get the following output,

<_io.TextIOWrapper name='test.txt' mode='w+' encoding='cp1252'>

Is there a way to open and then write in the file and then save it so I can use that new file somewhere else? Even though I have something written in the file, I still get this output.

possible duplicate of [Correct way to write line to file in Python](http://stackoverflow.com/questions/6159900/correct-way-to-write-line-to-file-in-python) — William Denman, Dec 14 '13 at 14:00
@tim thanks i just go confused. i now understand what i did wrong. — ruthless, Dec 14 '13 at 20:30

score 1 · Accepted Answer · edited Dec 14 '13 at 14:04

1

f = open("file.txt",'r+')
lines = f.readlines()
f.writelines(lines)
f.close()

edited Dec 14 '13 at 14:04

Tim

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answered Dec 14 '13 at 13:40

chanakya devraj

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How to open a text file in python?

1 Answers1