How will I perfom actionListener on a same thing again and again in a same class?

Question

What should I do if I want to perform an ActionListener on a button again and again, so that it will not give me the same ans again...

For example:

down = new JButton("DOWN-1");
down.setSize(down.getPreferredSize());
down.setLocation(100,200);
down.addActionListener(this);
left=new JButton("LEFT-1");
left.setSize(left.getPreferredSize());
left.setLocation(100,250);
left.addActionListener(this);
right=new JButton("RIGHT-1");
right.setSize(right.getPreferredSize());
right.setLocation(100,300);
right.addActionListener(this);
up1=new JButton("UP-2");
up1.setSize(up1.getPreferredSize());
up1.setLocation(550,150);
up.addActionListener(this);

@Override
public void actionPerformed(ActionEvent a)
{
    int counter=370;

    if (a.getSource()==up) {
        System.out.println(counter);

        x=250+62+62;
        y=60+62+62+62+62+62;
        b1.setLocation(x,counter-62);
        l19.setLocation(x,counter);
    }   
}

In this I want to use up button again and again but it is not working...

Your question is unclear. You also don't perform a listener, the listener is called when something happens. — zapl, Dec 14 '13 at 23:35
Oh wow, I accidentally deleted my comment, but here's the problem: `up.addActionListener(this);` should be `up1.addActionListener(this);` — iWumbo, Dec 14 '13 at 23:36
i know.... but i want to perform it again and again ....@zapl — Salman Aslam, Dec 14 '13 at 23:40
You attach (add) you listener to `up`. What is it and where is it defined? Also overall structure of your application is not clear. Do you create `JForm` (or another top container)? — PM 77-1, Dec 14 '13 at 23:40
If you want to perform the ActionListener again and again you have to carry out he action it is listening to again and again. Your question doesn't make any sense. — user207421, Dec 14 '13 at 23:50
Use `Action` as shown [here](http://stackoverflow.com/a/5797965/230513). — trashgod, Dec 15 '13 at 00:01

score 0 · Accepted Answer · answered Dec 15 '13 at 01:51

While your question is Sooo very confusing. I think I have been able to extract up some meaning to it. "...if I want to perform an ActionListener on a button again and again,...". My guess is that you mean you want to be able to use the button more than once.

This is what I'm seeing in your code that would make you think you're not able to use it more than once.

@Override
public void actionPerformed(ActionEvent a)
{
    int counter=370;

    if (a.getSource()==up) {
        System.out.println(counter);

        x=250+62+62;
        y=60+62+62+62+62+62;
        b1.setLocation(x,counter-62);
        l19.setLocation(x,counter);
    }   
}

What's happening is that ever click of the button, the location is always set to the same place. The initial location my be different, that's why it appears to be working on the first click (the location will change). But after that, every click leads to the same location, so whatever you expect to move, doesn't.

Though I have no idea what your code does, from your minimal "explanation" (if you can even call it that). I can give a suggestion. It seem that counter is the offsetting factor, so what you may want to do is give the counter a global scope and change its value every time the button is clicked. Something like this

int counter = 370;

@Override
public void actionPerformed(ActionEvent a)
{
    if (a.getSource()==up) {
        counter -= 62;         // this is where you change the value of counter

        System.out.println(counter);

        x=250+62+62;           // I have no idea what this is for
        y=60+62+62+62+62+62;   // or this, so I won't comment
        b1.setLocation(x,counter);   // just use the new counter value
        l19.setLocation(x,counter);
    }   
}

How will I perfom actionListener on a same thing again and again in a same class?

1 Answers1