Not case sensitive comparison of strings

Question

I have this currently (and much more) and want to make it so that if someone types something in from the array that isn't uppercase(it is currently all uppercase), then they can still order it.

if(food.equals(array[0])) {
    System.out.println("Here is your " + food + ".");
}

I have the code for it in other places, this is a small portion of code. — Durnehviir, Dec 16 '13 at 18:34
I knew, a question like this must have been already answered in StackOverflow, IMO — Sage, Dec 16 '13 at 18:37

score 5 · Answer 1 · edited Dec 16 '13 at 18:33

5

Use equalsIgnoreCase instead of equals.

edited Dec 16 '13 at 18:33

exexzian

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answered Dec 16 '13 at 18:32

Dawood ibn Kareem

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Thanks, it worked, wish I could accept earlier. – Durnehviir Dec 16 '13 at 18:34

score 3 · Answer 2 · answered Dec 16 '13 at 18:32

3

Use

food.equalsIgnoreCase(array[0])

It's documented, in the String API.

answered Dec 16 '13 at 18:32

Amir Afghani

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score 0 · Answer 3 · answered Dec 16 '13 at 18:33

0

Use equalsIgnoreCase() instead of equals()

answered Dec 16 '13 at 18:33

Rakesh KR

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score 0 · Answer 4 · answered Dec 16 '13 at 18:37

0

The other way to go about this is to ensure that everything stored in your array is lowercase, then do food = food.toLowerCase(); before testing whether food.equals() something in your array.

If you had a very tight performance requirement for this part of your application, you might choose to run the comparison this way.

answered Dec 16 '13 at 18:37

user1445967

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Another possibility is to create a Food class that knows how to compare itself case insensitively (overriding equals and hashCode), and use that instead of strings. – David Conrad Dec 16 '13 at 19:00

Not case sensitive comparison of strings

4 Answers4