properties file is not called while creating the jar

Question

I have created a java project in which I am using a properties file also which is created inside a java packgae named abcedf

so package name is abcdef which consists a class name abc.java and a property file named drg.properties ,now from class abc.java i am referring to that properties file as..

abc tt = new abc();
URL url = tt.getClass().getResource("./drg.properties");
File file = new File(url.getPath());
FileInputStream fileInput = new FileInputStream(file);

now this file is referred and my program runs successfully but when I am trying to make it executable jar then this property file is not referred please advise what is went wrong while creating the property file.

http://stackoverflow.com/questions/18250236/java-images-not-drawn-when-running-java-jar/18250364#18250364 Use URL.openStream() instead of new File()! — Luca Basso Ricci, Dec 17 '13 at 08:03
Please use proper Java naming conventions so that it will be easy to understand — Sachin, Dec 17 '13 at 08:05
@bellabax can you please explain in detail so that I can grasp.Thanks in advance — user3104732, Dec 17 '13 at 08:23

dARKpRINCE · Answer 1 · 2013-12-17T08:40:50.860

2

Use

tt.getClass().getResourceAsStream("./drg.properties");

to access the property file inside a JAR. You will get an InputStream as returned object.
-------------------------------------------------
Here is an example to load the InputStream to Properties object

InputStream in = tt.getClass().getResourceAsStream("./drg.properties");
Properties properties = new Properties();
properties.load(in); // Loads content into properties object
in.close();

If your case, you can directly use, the InputStream instead of using FileInputStream

edited Dec 17 '13 at 08:40

answered Dec 17 '13 at 07:59

dARKpRINCE

1,538
2
13
22

dARKpRINCE Thanks, can you also please explain in details about input stream object also – user3104732 Dec 17 '13 at 08:20
I have edited the answer to add an example. If this helped, please accept this answer. :) – dARKpRINCE Dec 17 '13 at 08:35

score 0 · Answer 2 · answered Dec 17 '13 at 08:51

When you access "jarred" resource you can't access it directly as you access a resource on your HDD with new File() (because resource doesn't live uncompressed on your drive) but you have to access resource (stored in your application jar) using Class.getResourceAsStream()

Code will looks like (with java7 try-with-resource feature)

Properties p = new Properties();
try(InputStream is = tt.getClass().getResourceAsStream("./drg.properties")) { 
 p.load(is); // Loads content into p object
}

properties file is not called while creating the jar

2 Answers2