Convert unix/epoch time to formatted date - unexpected date

Question

Im trying to convert a timestamp to a human readable date and time. I tried:

String dateSt = 1386580621268;
Log.i("*****", "date st is = "+dateSt);
long unixSeconds = Long.parseLong(dateSt);
Log.i("*******", "unix seconds is = "+unixSeconds);
Date date = new Date(unixSeconds*1000L); // *1000 is to convert seconds to milliseconds
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy"); // the format of your date
String formattedDate = sdf.format(date);
System.out.println(formattedDate);

The expected result is to be 09-12-2013, however i get 28-12-45908. The above example can be found at: Convert Unix timestamp to date java, answer by David Hofmann

score 16 · Answer 1 · answered Dec 18 '13 at 10:02

16

Try this,

public static String Epoch2DateString(long epochSeconds, String formatString) {
    Date updatedate = new Date(epochSeconds * 1000);
    SimpleDateFormat format = new SimpleDateFormat(formatString);
    return format.format(updatedate);
}

answered Dec 18 '13 at 10:02

No_Rulz

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score 3 · Accepted Answer · answered Dec 18 '13 at 10:04

3

1386580621268 is not a unix timestamp i.e. seconds since epoch for 9-12-2013 but milliseconds since epoch. Remove the *1000L or divide the input by 1000.

answered Dec 18 '13 at 10:04

laalto

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Ah i see, thank you very much for clearing that up. It works correctly now :) I just removed the `*1000L` like you suggested. Thanks again. – DevC Dec 18 '13 at 10:17

score 2 · Answer 3 · answered May 15 '19 at 10:21

I solved this way.

public static String Epoch2DateString(String epochSeconds) {
    Date updatedate = new Date(Integer.parseInt(epochSeconds) * 1000L);
    SimpleDateFormat format = new SimpleDateFormat("dd-MM-yyyy");
    return format.format(updatedate);
}

Convert unix/epoch time to formatted date - unexpected date

3 Answers3