Is it possible to create custom operators in JavaScript?

Question

During the Math classes we learned how to define new operators. For example:

(ℝ, ∘), x ∘ y = x + 2y

This defines ∘ law. For any real numbers x and y, x ∘ y is x + 2y.

Example: 2 ∘ 2 = 2 + 4 = 6.

---

Is possible to define operators like this in JavaScript? I know that a function would do the job:

function foo (x, y) { return x + 2 * y; }

but I would like to have the following syntax:

var y = 2 ∘ 2; // returns 6

instead of this:

var y = foo(2, 2);

Which is the closest solution to this question?

Answer 1

The short answer is no. ECMAScript (the standard JS is based on) does not support operator overloading.

As an aside, in ECMAScript 7, you'll be able to overload a subset of the standard operators when designing custom value types. Here is a slide deck by language creator and Mozilla CTO Brendan Eich about the subject. This won't allow arbitary operators, however, and the overloaded meaning will only be applied to value types. <- haha that ended up not happening.

It is possible to use third party tools like sweet.js to add custom operators though that'd require an extra compilation step.

I've answered with a solution from outside JavaScript using esprima - this is changing JavaScript and extending it, it's not native.

Answer 2

Given the somewhat new tagged template literals feature that was added in ES6 one can create custom DSLs to handle embedded expressions such as these including different algebraic symbols.

ex. (run in stackblitz)

function math(strings, x, y) {
  // NOTE: Naive approach as demonstration

  const operator = strings[1].replace(/\s/gi, "");

  if (operator == "∘") {
    return x + 2 * y;
  }
  else if (operator == "^") {
    return Math.pow(x, y);
  }
  else {
    return `Unknown operator '${operator}'`;
  }
}

console.log(math`${2} ∘ ${2}`)

Note that since tagged template literals don't necessarily return strings as results they can return more complex intermediate AST like structures to build up an expression that can then be further refined and then interpreted while keeping close to the domain specific language at hand. I haven't found any existing library that does this yet for Javascript but it should be an interesting and quite approachable endeavor from what it appears from what I know of tagged template literals and usage in such places as lit-html.

Answer 3

No. You can't do that in JS.

The closest you can have IMO is to implement your own object which has a chainable interface, aka "fluent" syntax. That way you can operate as if you were speaking out in sequence.

var eq = new YourEquationObject();

// Then operate like 1 - 2 * 3
eq.add(1).sub(2).mul(3);

Details are up to you though. Just giving out an idea.

Answer 4

You can add pseudo-operators via methods on Number.prototype:

Object.defineProperty(Number.prototype, 'myOp', {
    value: function(that) {
        return this + 2 * that;
    }
});

Then all of this syntax will work

alert( (2).myOp(2) )
alert( 2 .myOp(2) )
alert( 2..myOp(2) )
alert( 2.0.myOp(2) )

2.myOp(2) does not work because the period is treated as a decimal point

Answer 5

No. JavaScript does not support operator overloading . but you can make a class method for doing this

var mathClass = function(value){
   this.value = value;
}

mathClass.prototype.toLaw = function(){
   return 2 * this.value;
}

var y = new mathClass(2)
2 + y.toLaw(); //2 + 2 * y

Answer 6

Read the comments below the answer.

Apparently you can't. Here is something close :

function exec(input) {
    return Function(
        'return ' + input.replace(/∘( *[\d.]+)/g, '+ 2 * $1') + ';'
    )();
}

exec('2 ∘ 2'); // 6

Answer 7

Set of compiled to JS languages support custom operators.

I would highlight ReasonML (ocaml-syntax-readable-by-js-folks) and Bucklescript (ocaml-to-js-compiler) which makes custom operators look neat:

For example an operator to concatenate strings can look like:

let (>|<) = (list, seperator) => Belt.List.reduce(list, "", (a, b) => a ++ seperator ++ b);

which can then be used like:

[Styles.button, Media.Classes.atLeastTablet] >|< " "

The downside of all this is the fact it has to be written in such compiled-to-js language, and it comes with lots of pros and cons, but usually those languages have the appeal of tons of nice syntactic sugar you don't get in js/ts

Answer 8

The slightly longer then the short one is that Yes you can, but its a bit more involved then what you did in Math class

To extend the language with new constructs you can use a transformer like http://esprima.org/ or any of the others. You need to define your syntax, write the parser to parse your statement and finally add the actual code to do the math parts. When these parts is in place you have made a new language that works just as javascript but with the added support of the ∘ operator.

Its really not that hard to add new syntax, here is facebooks example how they add => arrow function syntax

https://github.com/facebook/jstransform/blob/master/visitors/es6-arrow-function-visitors.js

Answer 9

I was asking this question too, and here's my answer:

function myCustomOperation(string){
var res = String.fromCharCode(9762);
var thing = string.replace(/☢/g," + 10 + ");
thing=thing.replace(/☣/g," * 2 + ");
thing=thing.replace(/☠/g," / 3 * ");
return [eval(thing),string+" = "+eval(thing)];
};
var thing = myCustomOperation("

3 ☠ 4

");
document.write(thing[1]);

Answer 10

There are several tools, compilers, or language extensions providing such a possibility, and even using emojis and other stuff, that are uncommon in JavaScript itself. sweet.js is the closest one I can remember, and also another JavaScript compiled tool might be useful.

Answer 11

Since JS doesn't allow to define custom operators now and if you don't want to use complex solutions you can take a look on extending Number class with needed functions (operators), for instance:

Number.prototype.o = function(y) {
  return this + 2 * y;
};

// 2 ∘ 2

let n = 2;
const r1 = n.o(2);
console.log(r1); // Prints: 6

// OR

const r2 = (2).o(2);
console.log(r2); // Prints: 6

With this approach you can make complex math expressions by chaining operators each after another:

Number.prototype.pow = function(exponent) {
  return Math.pow(this,  exponent);
};

Number.prototype.sqrt = function() {
  return Math.sqrt(this);
};

// √((2 ∘ 2)² - 11)

const r3 = (((2).o(2)).pow(2) - 11).sqrt();
console.log(r3); // Prints: 5