Check if variable ends with

Question

i have the variable $uid that always contain a number. I want to execute different actions depending on how the $uid ends. For example:

if(&uid ENDS WITH 2,3 or 4) {echo "Some content"};
else if($uid ENDS WITH 1,5 or 6) {echo "Some other content"};
else if($uid ENDS WITH 7,8,9 or 0) {echo "Some other content"};

Nothing comes on my mind how to achieve this. Thanks in advance for Your time!

This really is a bad piece of design, I thought code flow based on actual variable name died out in the 70's - why not simply use an array and test on the key — Mark Baker, Dec 24 '13 at 15:54
This will help you. http://stackoverflow.com/questions/2681786/how-to-get-the-last-char-of-a-string-in-php — Mansoorkhan Cherupuzha, Dec 24 '13 at 15:57
Do you want the variable name to end with 2,3.. or the variable value? — Eisa Adil, Dec 24 '13 at 15:58

score 3 · Answer 1 · 2013-12-24T16:13:38.943

3

$end = substr($uid, -1);
if($end == 2 || $end == 3 || $end == 4){
echo "Some content";
}
else if($end == 1 || $end == 5 || $end == 6){
echo "Some other content";
}
else if($end == 7 || $end == 8 || $end == 9 || $end == 0){
echo "Some other content";
}

Update: If you know that $uid is an integer, you may change the first line to:
$end = $uid % 10;

edited Dec 24 '13 at 16:13

answered Dec 24 '13 at 15:55

Popnoodles · Answer 2 · 2013-12-24T16:02:12.533

There are a few ways to swing this cat. Using lots of if/elseif like you have, but that becomes hard to read. You can use in_array() which is a good solution, but again you have several if/elseifs.

I prefer to use a switch.

$end=substr($uid, -1);

switch ($end){
    case 2:
    case 3:
    case 4:
        echo "Some content";
        break;
    case 1:
    case 5:
    case 6:
        echo "Some other content";
        break;
    case 7:
    case 8:
    case 9:
    case 0:
        echo "Some other other content";
        break;
}

score 2 · Accepted Answer · answered Dec 24 '13 at 16:00

2

Try this:

    $endsWith = substr($uid, -1);
    if (in_array($endsWith, array(2, 3, 4)) echo "something";
    elseif () // ... etc

answered Dec 24 '13 at 16:00

dan

136
8

I tried: `` and it outputs error: `syntax error, unexpected T_ECHO in /var/www/dn/index.php on line 4` any suggestions? – mr.d Dec 24 '13 at 16:28

Check if variable ends with

3 Answers3