I have a Python script on my Raspberry Pi running on Arch Linux ARM. To start the script, I use this command:
sudo python2 screen/screen.py
and it works perfectly. Now, my question is, how I can run this script automatically on start-up?
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Why not like http://stackoverflow.com/questions/12973777/how-to-run-a-shell-script-at-startup ? – Daniel F Dec 25 '13 at 22:58
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Because I can't run the python code as an app. At least I don't know how... – Andrei RRR Dec 25 '13 at 23:02
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In the folder /etc/systemd/system/ make a file named screen.service
The contents of that file might look like this (change for your use):
[Unit]
Description=Launches screen with my config
After=network.target
[Service]
Type=simple
ExecStart=command_you_want_to_run
RemainAfterExit=true
[Install]
WantedBy=multi-user.target
When you're finished run systemctl enable screen.service
The WantedBy line tells systemd where to make the symlink.
To learn more about the options for service unit files check out the docs: man systemd.service
danielcooperxyz
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mdur
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@Cruncher: Try: `systemd --version`, this can confirm that you are using systemd. This list shows which distros have adopted systemd: http://en.wikipedia.org/wiki/Systemd#Adoption – mdur Nov 15 '14 at 03:29