C# generating random double number range

Question

Hi how can i generate a range of "double" numbers? For example how can i generate numbers between 2.50 and 7.20 There is a method in Random() class for "int" numbers Next(Int32, Int32) is there something similar for double?

score 8 · Accepted Answer · answered Dec 26 '13 at 13:23

You can write an extension method to Random for Random.NextDouble(double MinValue,double MaxValue) so that you can use it everywhere:

public static class RandomExtensions
{
    public static double NextDouble(this Random RandGenerator, double MinValue, double MaxValue)
    {
        return RandGenerator.NextDouble() * (MaxValue - MinValue) + MinValue;
    }
}

score 3 · Answer 2 · answered Dec 26 '13 at 13:15

3

Get a value from 0 to 1, then multiply it by 7.20 - 2.50 and add 2.50.

double result = (random.NextDouble() * (7.2 - 2.5)) + 2.5;

answered Dec 26 '13 at 13:15

ken2k

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score 1 · Answer 3 · answered Dec 26 '13 at 13:16

1

Yes, it's called Random.NextDouble(). This returns a double between 0 and 1.

var value = lower + (random.NextDouble() * (upper - lower))

will return what you need.

answered Dec 26 '13 at 13:16

Roy Dictus

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C# generating random double number range

3 Answers3