PHP: Grab empty parameter name ?123

Question

How can I grab an empty parameter name in PHP e.g. http://yoursite.com/?123 > "123" ?

I want to use this as URL shortener to redirect to the ID from the parameter.

Check the answer in this post, problem is simular: http://stackoverflow.com/a/255335/3143634 — Lexib0y, Jan 03 '14 at 00:21

score 0 · Answer 1 · edited Jan 03 '14 at 00:26

0

You have built-in function that will parse your URL parse_url() and string query parser parse_str():

$url = 'http://yoursite.com/?123&a=b&abc=';
$parsed = parse_url($url);
parse_str($parsed['query'], $query);
var_dump($query);

Keys in array $query that have empty string as value, are the keys you are looking for.

$filtered = array_filter($query, function($v) { return empty($v); });
#$filtered = array_keys($filtered);
print_r($filtered);

edited Jan 03 '14 at 00:26

Kornel

answered Jan 03 '14 at 00:22

Glavić

Thanks, but as dimimpou pointed out, `$_SERVER['QUERY_STRING']` does just fine. Added is_numeric() and whoop! – Martin Jan 03 '14 at 00:37
@Martin: I miss-understood the question, I thought you have URL saved in the variable. p.s. What if someone adds some custom parameters to the URL? Like `?test=abc&123` ? – Glavić Jan 03 '14 at 00:38
Oh, sorry. Then he fails which is fine for being a hacker :) – Martin Jan 03 '14 at 00:41
@Martin: `hacker`, lol ;) Some links are changed by google or FB, who append there own parameters. You should check that case scenario, and not leave it in the 'air' ;) – Glavić Jan 03 '14 at 00:44

score 0 · Answer 2 · answered Jan 03 '14 at 00:29

0

Use array_keys to fetch all keys.

var_dump(array_keys($_GET));

array(1) { 0 => "123" }

"123" will also appear if you iterate over $_GET, like with foreach.

answered Jan 03 '14 at 00:29

Halcyon

2 Answers2