How to get a string using pointer and print it again?

Question

I tried with the following code:

    #include<stdio.h>
    int main()
    {
    char *a;
    scanf("%s",a);
    printf("%s",a);
    return 0;
    }

I can enter a string but nothing is printed in the screen.

There are millions of examples of how to do this. Please, learn to do a little bit of research for yourself. — Jonathon Reinhart, Jan 03 '14 at 06:27
Look at this question and answer: http://stackoverflow.com/questions/16983174/whats-wrong-with-this-scanf — Phillip Kinkade, Jan 03 '14 at 06:28
possible duplicate of [making use of string pointer to print the character-integer combinations](http://stackoverflow.com/questions/4484376/making-use-of-string-pointer-to-print-the-character-integer-combinations) — Hamad, Jan 03 '14 at 06:51

score 0 · Accepted Answer · answered Jan 03 '14 at 06:29

0

By allocating some memory before using it.

char *a;
a=malloc(sizeof(char)*10);
scanf("%s",a);
printf("%s",a);
return 0;

answered Jan 03 '14 at 06:29

Digital_Reality

score 0 · Answer 2 · answered Jan 03 '14 at 06:33

0

char *a = (char *) malloc(512 * sizeof(char));

c is rigorous you should do all the preliminary work

answered Jan 03 '14 at 06:33

user3156041

Elaborate more on what this does and why it's necessary. As it stands, it's unclear to the OP why this could help. – arne Jan 03 '14 at 06:58

2 Answers2