Regular Expressions for string in php to find the word in commas

Question

I'm trying to write a Regexp for php to scan true files, the keyword is require and the string I want is in brackets "my string" (require would be reserved) example

File1.txt

require "testing/this/out.js"
require "de/test/as.pen"
require "my_love.test"

.....

print "I require coffee in the morning" //problem

The requires will be at the top of the page.
Follow the standard require "_String_" format

File2.txt

Class Ben extends Name

....

print "My good boss always extends my deadline" //problem

Extends would only be follow by class name
Is only one word and only one result

// looping true and determining if class or if reg file by folder structure
$subject = "Code above";
$pattern = '/^require+""/i'; // Not sure of the correct pattern
preg_match($pattern, $subject, $matches);
print_r($matches);

I just want testing this out and de/test/as.pen to return in an array for the first example.

Is this possible? will there be a lot of problems with this?

If I understand well, you want to be sure that `require` is not inside a string? — Casimir et Hippolyte, Jan 06 '14 at 20:54
Are you trying to build a map of the dependencies between your files by collecting the `require`, and classes extending other classes and so on ? I really don't understand what you're trying to do from the description of your problem, so I'm guessing... — Martin, Jan 06 '14 at 20:57
@Martin Yes im trying to build a dependency system. the regex is what I dont understand. Its the best way i think that will work. — Kivylius, Jan 06 '14 at 20:58
I would definitely use a parser and inspect the outputted AST for that. Look at http://stackoverflow.com/questions/5586358/any-decent-php-parser-written-in-php (Here's the parser he wrote : https://github.com/nikic/PHP-Parser). If you don't know what an AST is : http://en.wikipedia.org/wiki/Abstract_syntax_tree — Martin, Jan 06 '14 at 21:03

score 1 · Answer 1 · answered Jan 06 '14 at 20:55

1

You can use this regex:

$pattern = '/^ *require +"([^"]+)"/i';

answered Jan 06 '14 at 20:55

anubhava

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Should this be a case sensitive regex? – David Knipe Jan 06 '14 at 21:05
Probably not, I just copied that part from question – anubhava Jan 06 '14 at 21:15

revo · Answer 2 · 2014-01-07T08:29:31.977

1

^require (['"])([.\w /]+)\1

match the result:

preg_match('#^require (['"])([.\w /]+)\1#', $code, $match);

Explanation:

^               #  Start of string
require         #  reserved word with an space after
(['"])          #  Quotations
(               #  Capturing group
    [.\w /]+    #   Any possible characters
)               #  End of capturing group
\1              #  Same quotation

Demo

edited Jan 07 '14 at 08:29

answered Jan 06 '14 at 20:58

revo

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Your question is very correct but its not working correctly. Check out this js Fiddle: http://jsfiddle.net/CezarisLT/zcFEm/4/ Its almost works but the require is included. `/gm` are just two global/mutlyline flags. – Kivylius Jan 06 '14 at 22:19
@CezarisLT You should refer to 2nd captured group. check it here http://jsfiddle.net/fcCP4/ – revo Jan 07 '14 at 08:27

score 0 · Answer 3 · answered Jan 06 '14 at 21:06

The idea is to skip content inside quotes:

$pattern = <<<'LOD'
~
(["']) (?> [^"'\\]++ | \\{2} | \\. | (?!\1)["'] )* \1 # content inside quotes
(*SKIP)(*FAIL)  # forces this possibility to fail
|
(?>^|\s)
require \s+ " ([^"]++) "
~xs
LOD;

preg_match_all($pattern, $subject, $matches, PREG_SET_ORDER);
print_r($matches);

Regular Expressions for string in php to find the word in commas

3 Answers3