C++ cout errors whenever it tries to print a function variable

Question

I can use cout to print a normal variable just fine, but whenever I try to print a function variable(in this case, string input) the compiler shoots out the error:

C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::string' (or there is no acceptable conversion)

I have posted my code below. Is there anything that I am doing wrong?(I am using the C++ version of Eclipse)

Here's my code so far:

#include <iostream>
using namespace std;

void println(string text) {
    cout << text << endl;
}

int main() {
    int test = 5;
    cout << test;
    return 0;
}

Thanks for the answer! Make sure to put the answer as an answer, instead of a comment, so I can mark it as an answer and give you rep! — Drew, Jan 06 '14 at 23:12
I would add an answer, but I [already answered this the other day](http://stackoverflow.com/questions/20939089/no-operator-matches-these-operands/20939121#20939121). — juanchopanza, Jan 06 '14 at 23:17

score 0 · Accepted Answer · answered Jan 06 '14 at 23:17

If you want to use std::string, you need to include <string>! The type may be declared or even defined because it is used by the IOStream classes but the implementation may choose not to include the entire header. In your code it seems you got a definition of std::string but not the declaration of its output operator.

score 0 · Answer 2 · answered Jan 06 '14 at 23:36

0

Operator << for class std::basic_string are declared in header <string>. So you need to include it in your program that the compiler will know about it.

answered Jan 06 '14 at 23:36

Vlad from Moscow

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C++ cout errors whenever it tries to print a function variable

2 Answers2