I've a parameterized interface:
public interface MyInterface<T> {
void run(T e);
}
And classes implementing the interface:
public class MyClass1 implements MyInterface<SomeOtherClass1> {
public void run(SomeOtherClass1 e) {
// do some stuff with e
}
}
public class MyClass2 implements MyInterface<SomeOtherClass2> {
public void run(SomeOtherClass2 e) {
// do some stuff with e
}
}
The number of different MyClass*X* is known and exhaustive, and there is only one instance of each MyClass*X*, so I would like to use an enum:
public enum MyEnum {
MY_CLASS_1,
MY_CLASS_2;
}
To be able to use MyEnum.MY_CLASS_1.run(someOtherClass1);
for example (I would then have every instance of MyInterface in one same place). Is it even possible (and if yes, how)? Because I'm quite stuck for now...
What I tried yet:
public enum MyEnum {
MY_CLASS_1(new MyClass1()),
MY_CLASS_2(new MyClass2());
private MyInterface<?> instance;
private MyEnum(MyInterface<?> instance) {
this.instance = instance;
}
public void run(/* WhichType? */ e) {
instance.run(e);
}
}
In the above method, when using the type Object for the e
parameter:
public void run(Object e) {
instance.run(e);
// ^^^
// The method run(capture#3-of ?) in the type MyInterface<capture#3-of ?> is not applicable for the arguments (Object)
}
The problem I think is with that private MyInterface<?> instance
field: I need to know how is the instance parameterized, using something like private MyInterface<T> instance
, but I can't find a working solution...
In short, I'm stuck ;)
PS: since the run
methods bodies can be quite long, I'm trying to avoid anonymous classes within the enum:
public enum MyEnum {
MY_CLASS_1 {
/* any method, etc. */
},
MY_CLASS_2 {
/* any method, etc. */
},
}
MyEnum
would then become totally unreadable.
solutionworkaround if I don't want to redesign the job... But I guess I would better redesign it without an enum ;) Thank you anyway, such a shame enums can't manage these kinds of generics! – sp00m Jan 08 '14 at 08:51