Get XML value from xpath with namespace

Question

To be clear, my xml and its XPath are dynamic, anything may come, so no hard coded values to parse XML value from XPath. Here is my XML and XPath constructed.

String xml = "<soapenv:Envelope xmlns:com=\"http://com\" xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\"><soapenv:Header/><soapenv:Body><com:addition><com:a>1</com:a><com:b>1</com:b></com:addition></soapenv:Body></soapenv:Envelope>";
Document doc = UtilityFunction.createXMLDocument(xml);
System.out.println("Value "+XPathFactory.newInstance().newXPath().compile("//soapenv:Envelope[1]/soapenv:Body[1]/com:addition[1]/com:a[1]").evaluate(doc).toString());

Empty is getting printed. How can I use namespace to get XML value from xpath. How to enable namespace in compilation.

possible duplicate of [how to retrieve XML data using XPath which contains namespace in Java?](http://stackoverflow.com/questions/8221652/how-to-retrieve-xml-data-using-xpath-which-contains-namespace-in-java) — aalku, Jan 09 '14 at 08:39

score 0 · Answer 1 · answered Jan 10 '14 at 04:21

XPathFactory.newXPath() returns an XPath object.

Create a NamespaceContext object, set it up to know about your namespace bindings, and call .setNamespaceContext() on the XPath object.

Then compile the XPath and invoke as usual.

(I presume this duplicates answers given in some of the "Related" questions at right, so I'm not going to give a code sample. It's simple enough.)

Get XML value from xpath with namespace

1 Answers1