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I am the OP for the question: Extending a class in which I received an excellent answer. However, as I try to compile the code (reworked slightly for my project) I received the following message (line no. changed to reflect following sample code):

except.h: | 09 | expected nested-name-specifier before ‘handler_t1’

along with many more which seem to stem from this line. I am brand new to C++, and my research into the answer (and the forthcoming problem) has yielded this fact: Microsoft's compiler seems to accept the code, but standards compliant ones do not.

The code as I currently have it is as follows:

#include <vector>
namespace except
{
  // several other classes and functions which compile and work already
  // (tested and verified) have been snipped out. Entire code is over
  // 1000 lines.

  class Error_Handler
  {
    public:
      using handler_t1 = bool (*)(except::Logic const&);
      std::vector<handler_t1> logic_handlers;

      // a lot more removed because the error has already happened ...
  }
}

A read through of the code in the linked question indicates to me (with my limited knowledge) that it should all work.

My question therefore is: What do I need to change in this declaration/definition to enable this to compile with gcc (4.6.3 64 bit linux compiling with -std=C++0x)?

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Jase
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3 Answers3

9

GCC 4.6.3 doesn't support C++11 type aliases: using handler_t1 = bool (*)(except::Logic const&);. Non-template type aliases are equivalent to typedefs: typedef bool (*handler_t1)(except::Logic const&);. Replace them and see if that helps.

Or even better, upgrade to a more recent compiler version. I believe the regular responders here tend to write to the portion of the language compiled by GCC 4.8.

EDIT: The only other iffy feature I see in that answer is range-based-for, which I believe GCC added support for in 4.6. You should be OK after replacing the type aliases with typedefs.

Casey
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    I found the relevant standard quote. `7.1.3.2 A typedef-name can also be introduced by an alias-declaration. The identifier following the using keyword becomes a typedef-name and the optional attribute-specifier-seq following the identifier appertains to that typedef-name. It has the same semantics as if it were introduced by the typedef specifier. In particular, it does not define a new type and it shall not appear in the type-id.`. Also, http://gcc.gnu.org/gcc-4.6/cxx0x_status.html. You'll see a big red no next to `template alises`. –  Jan 10 '14 at 04:26
  • @remyabel Excellent reference. Being new to C++ I had no idea that different compilers required different syntax, or offered different feature sets. – Jase Jan 10 '14 at 06:21
1

I also got the same problem and it solved by just upgrading go G++ 4.8 in my Ubuntu.

I assume that you already have a former version of gcc, the easiest way could be adding PPA to your repositories and Update and upgrade you can have the latest version with no worries:

sudo add-apt-repository ppa:ubuntu-toolchain-r/test

sudo apt-get update

this will add the new PPA to the other sources.

Then unistall the alternative:

sudo update-alternatives --remove-all gcc

sudo update-alternatives --remove-all g++

then:

sudo apt-get install gcc-4.8

sudo apt-get install g++-4.8

and as the alternative packages install :

sudo update-alternatives --install /usr/bin/gcc gcc /usr/bin/gcc-4.8 20

sudo update-alternatives --install /usr/bin/g++ g++ /usr/bin/g++-4.8 20

sudo update-alternatives --config gcc

sudo update-alternatives --config g++

at the end:

sudo apt-get update

sudo apt-get upgrade -y

sudo apt-get dist-upgrade

Hope this changes the --version ;)

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smali
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1

With g++ before version 6 you need the option --std=c++11 to be able to use the using directive.

rwst
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  • Especially since I was working with a version higher than 4.8, but lower than 6 – SDG Oct 26 '18 at 20:37