Django URL template match (everything except pattern)

Question

I need a django regex that will actually work for the url router to do the following:

Match everything that does not contain "/api" in the route.

The following does not work because django can't reverse (?!

r'^(?!api)

Answer 1

The usual way to go about this would be to order the route declarations so that the catch-all route is shadowed by the /api route, i.e.:

urlpatterns = patterns('', 
    url(r'^api/', include('api.urls')),
    url(r'^other/', 'views.other', name='other'),
    url(r'^.*$', 'views.catchall', name='catch-all'), 
)

Alternatively, if for some reason you really need to skip some routes but cannot do it with the set of regexes supported by Django, you could define a custom pattern matcher class:

from django.core.urlresolvers import RegexURLPattern 

class NoAPIPattern(RegexURLPattern):
    def resolve(self, path):
        if not path.startswith('api'):
            return super(NoAPIPattern, self).resolve(path)

urlpatterns = patterns('',
    url(r'^other/', 'views.other', name='other'),
    NoAPIPattern(r'^.*$', 'views.catchall', name='catch-all'),
)

Answer 2

Use a negative look behind like so:

r'^(?!/api).*$'

This link explains how to do that:

http://www.codinghorror.com/blog/2005/10/excluding-matches-with-regular-expressions.html

Answer 3

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