json_encode() can't return html

Question

I'm trying to return some code snippets from php to jquery. Everything works ok, but when I try to return html with <body> and <html> tags then I get my javascript code in output (raw code)

this is my code:

$snippetData['snippetId'][] = $snippetId;
$snippetData['title'][] = $title;
$snippetData['description'][] = $description;
$snippetData['snippet'][] = $code;
echo json_encode($snippetData);

EDIT:

To make it more clear this is what I store in this array:

snippedId = 5 (integer value)
title = 'some title'  (string value)
description 'some description' (string value)
snippet = '<html> <body> <title>some title </title> </body> </html>' (string value)

Can you show us what this script echos? Where and how are you using the echoed values? I see nothing wrong with this code. — gen_Eric, Jan 10 '14 at 21:57
It is valid JSON, and not just *real* HTML you're trying to parse ? — adeneo, Jan 10 '14 at 21:58
$snippetData contains just dummy data, for testing. And in 'code' part it contains simple html with body, title and one dummy label. — Alen, Jan 10 '14 at 21:59
@Alen: Is that *exactly* what was generated by this script? Or did you modify it in any way? That JSON is invalid, and I've *never* seen `json_encode` generate invalid JSON. — gen_Eric, Jan 10 '14 at 22:01
@RocketHazmat Yes, this is exactly what was generated, I copied complete output — Alen, Jan 10 '14 at 22:01
How is the snippet `$code` generated? Is this some html/js code you wrote yourself? — tenub, Jan 10 '14 at 22:08
@Alen: What are you doing with this JSON? How are you using it? — gen_Eric, Jan 10 '14 at 22:10
Actually, you are not storing what you say. For example, snippetId contains an array of a single integer, not an integer value. You are making an array of arrays. — Guillermo Gutiérrez, Jan 10 '14 at 22:10

jdp · Accepted Answer · 2017-09-15T16:55:45.640

6

Try this:

<?php echo json_encode($snippetData, JSON_HEX_QUOT | JSON_HEX_TAG);

Source

edited Sep 15 '17 at 16:55

answered Jan 10 '14 at 22:10

jdp

3,446
2
30
54

This escapes html, but when I try to decode it in jquery I get this (this wierd code is generated in place where normally should be head tag): http://pastebin.com/05K1yx3w – Alen Jan 10 '14 at 22:28

score 1 · Answer 2 · answered Jan 10 '14 at 22:14

seems something is wrong with " char. try escaping them or base64 encode on html in json,

after getting data you can decode it.

ie you'll have:

JzxodG1sPiA8Ym9keT4gPHRpdGxlPnNvbWUgdGl0bGUgPC90aXRsZT4gPC9ib2R5PiA8L2h0bWw+Jw==

instead of

'<html> <body> <title>some title </title> </body> </html>'

when you decode, you'll get your snippet back

json_encode() can't return html

2 Answers2