how can i return control from java swing frame to normal java code

Question

am developing a java application in which I am using swings to develop GUI screens. i am supposed to run some application files. which I did by connecting to command prompt by using Runtime.exec() method. if my application failes to execute properly then a GUI frame will come up asking weather to run that file again or to skip.

here my problem is when I say run that file again the control should return to the point where the frame is called using ui.setvisible(true);

if not the swing frame what can i use to make my code work

public static boolean runFormat(String format,String buildNumber) throws Exception
{
try{
        ProcessExecutor process = new ProcessExecutor();
         process.executeCommand(format+"\\Scripts"+File.separator+"Step1.bat"+""+"02_00"+" "+format);
        process.waitForCompletion();
        File file = new File(format+File.separator+"Results1.log");
        BufferedReader read = new BufferedReader (new FileReader(file));
        String line;
        while((line=read.readLine())!=null)
        {
            if(line.contains("Successful exit."))
    {
                return true;
    }
        }
        return false;
}
catch(Exception e)
    {
        System.out.println("EXCEPTION OCCURED..................");
        System.out.println("JTag has failed for "+format);
        e.printStackTrace();
}
    return true;
}
    void run(Set<String> formats)
    {
        try
        {
        for(String ar : formats)
        {
            boolean b =runFormat(ar,"001");
            if(b==false)
            {
                ExampleUi ui = new ExampleUi();
                ui.setVisible(true);
            }
        }
        }
        catch(Exception e)
        {

        }
    }

Thanks in advance

What does your description have to do with your question title exactly? Also can you provide some code so we can better understand what you are trying to achieve? — Paul Samsotha, Jan 13 '14 at 03:18
"what can i use to make my code work" - More/better code. Hard for us to help without a [MCVE](http://stackoverflow.com/help/mcve) — Java Devil, Jan 13 '14 at 03:31
from above code i will call the GUI screen and when i give click on button in screen i should return to run method — user2572003, Jan 13 '14 at 03:38
You should edit your post to include the code. It will be formated and syntax highlighted and then delete those comments — Java Devil, Jan 13 '14 at 03:40

score 0 · Accepted Answer · answered Jan 13 '14 at 03:34

0

The short answer is no.

The long answer would involve using a SwingWorker and making the decisions about what to do within it's done method

Take a look at Worker Threads and SwingWorker for more details...

public class ProcessWorker extends SwingWorker<Boolean, Void> {
    public Boolean doInBackground() throws Exception {
        ProcessBuilder pb = new ProcessBuilder(...);
        Process p = pb.start();
        // Read the input stream in separate thread...
        return p.waitFor() == 0;
    }

    public void done() {
        try {
            boolean okay = get();
            if (!okay) {
                // Re-run....?
            }
        } catch (Exception exp) {
            // Show error message, maybe in a JOptionPane
        }
    }
}

answered Jan 13 '14 at 03:34

MadProgrammer

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Hi am in the above code will get invoke the doInBackground method ???????????? am sorry i have never used swingWorker class – user2572003 Jan 13 '14 at 06:15
Something like `new ProcessWorker().execute()`, take a look at the linked tutorial – MadProgrammer Jan 13 '14 at 06:19
my code is working properly when i debug but when i run its getting terminated with out executing anything – user2572003 Jan 13 '14 at 06:55
Do you have some kind of frame visible on the screen? – MadProgrammer Jan 13 '14 at 06:57
i dint use any frames just i used some conditions to print msg. i 1st wanted to practise – user2572003 Jan 13 '14 at 06:59
SwingWorker probably utilising a daemon thread, meaning that the jvm is free terminate almost immediately. Have a look at [this](http://stackoverflow.com/questions/15396694/swing-message-doesnt-get-displayed-until-after-runtime-getruntime-exec-fini/15398441#15398441) and [this](http://stackoverflow.com/questions/15801069/printing-a-java-inputstream-from-a-process/15801490#15801490) examples... – MadProgrammer Jan 13 '14 at 07:02
public static void runInBackgroud(final String msg) { SwingWorker task = new SwingWorker ( ) { public Boolean doInBackground() { System.out.println(msg); return true; } public void done(){try {Boolean b= get(); if(b==true) { System.out.println("correct hai"); } else { System.out.println("in correct hai"); }} catch (Exception e) {} }};task.execute ( ); } } – user2572003 Jan 13 '14 at 07:02
No the frame is not visible :( – user2572003 Jan 13 '14 at 08:08
If you're just testing the SwingWorker, just create a simple frame that you can make visible while you test it – MadProgrammer Jan 13 '14 at 08:32
yes.... i did thats what is the problem when i debug its working fine but when i run its doing nothing........... – user2572003 Jan 13 '14 at 08:57

how can i return control from java swing frame to normal java code

1 Answers1