How to print some text exactly in bash

Question

How do I print some text (in this case another bash script) exactly to some output file in bash?

So essentially I want to do something equivalent to the following but with special conditions:

echo [some multiline bash script] > output.bash

and output.bash would contain [some multiline bash script] exactly and no variable substitution occur

Have a look at [this SO Question](http://stackoverflow.com/q/2953081/205936). — S.R.I, Jan 14 '14 at 04:16
Also, you don't want variable interpolation to occur, you can quote the 'Limit String' as shown [here](http://tldp.org/LDP/abs/html/here-docs.html). Look for 'Parameter substitution turned off' or just copy the entire script into `output.bash`. — S.R.I, Jan 14 '14 at 04:21

score 0 · Answer 1 · answered Jan 14 '14 at 04:18

0

cat [some multiline bash script] > output.bash

answered Jan 14 '14 at 04:18

rejin

score 0 · Answer 2 · answered Jan 14 '14 at 06:07

0

print some text to file.name

cat >> file.name <<EOF
# base script 
ls
ls
cd ..
#...
EOF

answered Jan 14 '14 at 06:07

pexeer

score 0 · Answer 3 · answered Jan 14 '14 at 08:37

use single quote ''

like this '\' is for multi line input

#oyss=2
#echo '$oyss \
> $oyss line 2
> ' > 1.txt

#cat 1.txt
$oyss\
$oyss line 2

if you use double quote "".you will get the variable evaluated.

#echo "$oyss\
> $oyss line 2
> "
22 line 2

3 Answers3