Php Javascript Variable Syntax Error

Asked Jan 15 '14 at 22:08

Active Jan 15 '14 at 22:20

Viewed 121 times

I have this PHP code, which try to get the description of a YouTube channel, and run it in a JS file (xhr_object), and I've got this error : Unexpected token ILLEGAL. But I found the problem : $channel_descr contains a simple quote in somes cases, which break the JS code. I've already tried to use str_replace() but it doesn't change anything..

$json = file_get_contents("...?alt=json&part=snippet");
$data = json_decode($json, true);

$channel_descr = $data['entry']['content']['$t'];
$channel_descr = str_replace("\"", "&sbquo;", $channel_descr);
echo "alert (".$channel_descr.");";

Thanks.

EDIT

echo "alert ('".$channel_descr."');"; //Same Error

edited Jan 15 '14 at 22:20

asked Jan 15 '14 at 22:08

user3185672

you'll need quotes around `$channel_descr` – 1252748 Jan 15 '14 at 22:12
I've tested this. Same error : Unexpected token ILLEGAL – user3185672 Jan 15 '14 at 22:19
this http://stackoverflow.com/questions/12719859/syntaxerror-unexpected-token-illegal can be tricky.. – 1252748 Jan 15 '14 at 22:21
It might help be helpful to encode the string with `htmlentities` in PHP: http://www.php.net/manual/en/function.htmlentities.php – Mehdi Jan 15 '14 at 22:31
I finally found a solution : str_replace("\n", " ", $channel_descr); Thanks to all :) – user3185672 Jan 15 '14 at 23:48

Php Javascript Variable Syntax Error

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