how increment operator works in java

Question

int x=0;
x=x++;

System.out.println("The Value Of X-->"+x);

It will print 0 but why?

If we write the following code,

int x=0,y=0;
y=x++;

System.out.println("The Value Of Y-->"+y);
System.out.println("The Value Of X-->"+x);

Then the output will be 0 and 1. My question is in my first code first I put the x value to 0 then increment x so the x which value is 0 is replaced by 1,so the result should be 1 but here we got result is 0.

score 1 · Answer 1 · answered Jan 22 '14 at 10:23

1

x = x++

Increments x but then it returns its old value.

You should only do

x++

to increment x by 1.

answered Jan 22 '14 at 10:23

Andrea

6,032
2
28
55

1

I think it is - the question does say: ' My question is in my first code' Oops - looks like a mutating question issue (don't you just hate that!) – Jackson Jan 22 '14 at 10:27
my bad, apparently bad formatting was my downfall – Ross Drew Jan 22 '14 at 10:31

how increment operator works in java

1 Answers1