error trasfering php array to javascript

Question

I have this array:

$men['display']=array( 
                  "edit"        =>"1", 
                  "description" =>"2", 
                  "phone"       =>"3", 
                  "mail"        =>"4" 
                 );

I tried to transfer it to javascript by using:

<?php $disArray = json_encode($men['display']);?>

then, I sent it to javascript:

<select id="selectBoxHere" onChange="loadInnerHTML('<?php $disArray ?>')";>

For some reason, my javascript function 'loadInnerHTML' dosen't send my array to javascript.

You're sending a JSON string to `loadInnerHTML()`, not an array. Either remove the `''` around `` or parse the string into an array with `JSON.parse()` Also, you're not echoing the variable. — crush, Jan 27 '14 at 15:01
its a javascript function. I'm trying to pass a php array to a different page using ajax. — user3164596, Jan 27 '14 at 15:01
You need to decode Json coming from php. read : [enter link description here][1] [1]: http://stackoverflow.com/questions/4935632/how-to-parse-json-in-javascript — cyberpro4, Jan 27 '14 at 15:03
@user976990 Uh, no. If you hand it to javascript right (see my answer below) you don't need to decode. — jszobody, Jan 27 '14 at 15:05
When i remove the '' around the php code i get: Uncaught SyntaxError: Unexpected token ; — user3164596, Jan 27 '14 at 15:09

jszobody · Answer 1 · 2014-01-27T15:07:25.583

You forget the echo statment.

And if you use single quotes, it makes this a string. For a javascript object you don't need the single quotes, json_encode will ensure it is javascript safe.

loadInnerHTML(<?php echo $disArray ?>)

I'd also recommend that you store this variable directly in javascript first, rather than passing it into a function. Otherwise you have to worry about double quotes inside double quotes, breaking your <select> tag.

var disArray = <?php echo $disArray ?>;

Then you can just use that variable.

loadInnerHTML(disArray)

score 0 · Answer 2 · answered Jan 27 '14 at 15:15

0

Echoing an array in php will result in

var dis_array = Array

which js couldn't understand. Try:

var disArray = JSON.parse( '<?php echo json_encode( $disArray  ) ?>' );

answered Jan 27 '14 at 15:15

cyberpro4

1
1

error trasfering php array to javascript

2 Answers2