opening new window with jquery

Question

I have a ajax call that sends a value to the Servlet and Servlet creates a html file then returning the absolute path of the html file that has been created.
In response from the server is

"C:\Users\Ker\Documents\NETBEANS PROJECT\Titanium\build\web\default\result.html"

and in the ajax

 $(function() {
            $("#BTNRUN").click(function() {

                var html = $("#HTML").val();
                var body1 =html.replace('%','^');
                var body2=body1.replace('&','|');
                var css = $("#CSS").val();
                var js = $("#JS").val();
                var dataString = 'RUN=1&BODY=' + body2
                        + '&CSS=' + css + '&JS=' + js;
                $.ajax({
                    type: "POST",
                    url: "TitaniumServlet",
                    data: dataString,
                    success: function(data) {
                        window.open(data);
                    }
                });
                return false;
            });
        });

it opens a new browser but i alway go to about:blank page. is there something wrong with the adress?

edit:

try {

main_path is the context path of the project

        File file = new File(main_path + "\\result.html");
        if (file.createNewFile()) {
            System.out.println("File is created!");
        } else {
            System.out.println("File already exists.");
            file.delete();
            file.createNewFile();
        }
        writer = new PrintWriter(new FileOutputStream(file, false));
        writer.write(html codes here);
        return file.getAbsolutePath();
    } catch (FileNotFoundException ex) {
        Logger.getLogger(ProcessRun.class.getName()).log(Level.SEVERE, null, ex);
    } catch (IOException ex) {
        Logger.getLogger(ProcessRun.class.getName()).log(Level.SEVERE, null, ex);
    }

Try showing what the variable "data" is. After this line "success: function(data) {" add "console.log(data);" What came out in console? — Miguel Jiménez, Jan 28 '14 at 06:38
@migueljimenezz i mentioned the value of data "C:\Users\Ker\Documents\NETBEANS PROJECT\Titanium\build\web\default\result.html" — the bosxcz, Jan 28 '14 at 06:39
Sorry. Could be the problem that data has no protocol? Since the path is not in a server, put file:/// before data: window.open('file:///' + data); — Miguel Jiménez, Jan 28 '14 at 06:42
Possible duplicate: http://stackoverflow.com/questions/3582671/how-to-open-a-local-disk-file-with-javascript — Control Freak, Jan 28 '14 at 07:52
you may use relative path to your file because your file is created in context of your application. — Yagnesh Agola, Jan 28 '14 at 08:52

score 0 · Answer 1 · answered Jan 28 '14 at 09:29

As per my understanding you have created your file and store on context path of your application. If your new created file is in context path than you can directly use relative path or context path to access your file your open it in new window using your server address.

Your servelet code include below line to get context path :

 //after your line writer.write(html codes here);  

String serverAddrs = request.getServerName()+":"+request.getServerPort();
String contextPath = "http://"+serverAddrs + main_path ;   
                                   //main_path  is your context path
contextPath = contextPath+"/result.html";
System.out.println(contextPath);  
return contextPath;

opening new window with jquery

1 Answers1