how to unwrap an array in php

Question

i have this array here:

Array
(
 [0] => Array
     (
         [presentation] => Präsentationen
     )

 [1] => Array
     (
         [news] => Aktuelle Meldungen
         [devplan] => Förderprogramme
         [salesdoc] => Vertriebsunterlagen
     )

 [2] => Array
     (
         [user/settings] => Mein Account
     )

 [3] => Array
     (
     )

 [4] => Array
     (
         [orders] => Projekte
     )

)

i want to unwrap the first depth of the array to get this:

 Array
 (
  [presentation] => Präsentationen
  [news] => Aktuelle Meldungen
  [devplan] => Förderprogramme
  [salesdoc] => Vertriebsunterlagen
  [user/settings] => Mein Account
  [orders] => Projekte
 )

nothing, i know some ways to do this, but the are all ugly :) — antpaw, Jan 27 '10 at 12:32

score 22 · Accepted Answer · edited Jun 10 '14 at 10:09

22

With PHP 5.3.0+:

array_reduce($array, 'array_merge', array());

edited Jun 10 '14 at 10:09

Clement Herreman

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answered Jan 27 '10 at 12:23

Ignacio Vazquez-Abrams

776,304
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2

Beautiful one-liner, but I still have to go with Gordon's approach, it seems simpler to me. – Pekka Jan 27 '10 at 12:25
4

I like this one better than mine, because it works for an arbitrary amount of arrays on the first level – Gordon Jan 27 '10 at 12:25
wow this looks cool, but it doesnt work for me :( array_merge() [function.array-merge]: Argument #1 is not an array, but im 100% sure its the same array form the example. – antpaw Jan 27 '10 at 12:28
Works perfectly here, but I have a different structure: Before: `array(2) { [0]=> array(1) { ["a"]=> int(1) } [1]=> array(1) { ["b"]=> int(2) }}` After: `array(2) { ["a"]=> int(1) ["b"]=> int(2)}` – Ignacio Vazquez-Abrams Jan 27 '10 at 12:33
I also wonder why this works, as I tried it myself in another context without success. In comments on the `array_reduce` documentation site, someone says: "If $initial parameter is not an int, array_reduce passes 0 (zero) to the callback function". This way exactly my problem. So why does it work in your case? Also the method signature says: `(array $input , callback $function [, int $initial ])` note **`int $initial`**. – Felix Kling Jan 27 '10 at 13:34
I have PHP 5.3.1 here. It might be broken in some older versions. – Ignacio Vazquez-Abrams Jan 27 '10 at 13:37
Ok I think I found it, this was introduced in PHP 5.3.0 : "Changed array_reduce() to allow mixed $initial." Maybe you should put this in your answer. – Felix Kling Jan 27 '10 at 13:39

score 5 · Answer 2 · answered Jan 27 '10 at 12:22

5

I guess the simplest way is to use a foreach loop:

 $resultArray = array();

  foreach ($myArray as $array)
   foreach ($array as $key => $element)
    $resultArray[$key] = $element;

answered Jan 27 '10 at 12:22

Pekka

442,112
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@Pekka - yep, I'm just not with it today. – karim79 Jan 27 '10 at 12:23
@karim79, that happens sometimes. But @Gordon beat us both, his solution is definitely the best. – Pekka Jan 27 '10 at 12:24

Gordon · Answer 3 · 2010-01-27T12:27:24.720

4

Try

array_merge($array[0], $array[1], $array[2], $array[3], $array[4]);

or

$new = $array[0] + $array[1] + $array[2] + $array[3] + $array[4];

edited Jan 27 '10 at 12:27

answered Jan 27 '10 at 12:22

Gordon

312,688
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score 1 · Answer 4 · answered Jan 27 '10 at 12:28

1

This is also a beautifull one liner

$array = new RecursiveArrayIterator($yourArray);

answered Jan 27 '10 at 12:28

streetparade

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this also doesn't work for me, it doesn't change the input array in any way. – antpaw Jan 27 '10 at 12:34
You'd have to wrap that into an RecursiveIteratorIterator as well to be able to iterate over the first level elements. Also, $array won't be an array but, like the classname suggests, an iterator, wrapping an array. – Gordon Jan 27 '10 at 12:38

score 1 · Answer 5 · answered Nov 20 '18 at 09:27

1

With PHP 5.6.0+:

$new = array_merge(...$array);

(A more general version of Gordons approach.)

answered Nov 20 '18 at 09:27

Johannes Buchholz

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how to unwrap an array in php

5 Answers5