I am studying context switching in C programming and have found the following example code on the Internet. I am trying to figure out whether only makecontext()
function can trigger a function that does something. The other functions such as setcontext()
, getcontext()
, and swapcontext()
are used for setting the context.
The makecontext()
attaches a function and its parameter(s) to a context, does the function stick to the context all the time until a change is committed to it?
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <ucontext.h>
4 #define MEM 64000
5
6 ucontext_t T1, T2, Main;
7 ucontext_t a;
8
9 int fn1()
10 {
11 printf("this is from 1\n");
12 setcontext(&Main);
13 }
14
15 void fn2()
16 {
17 printf("this is from 2\n");
18 setcontext(&a);
19 printf("finished 1\n");
20 }
21
22 void start()
23 {
24 getcontext(&a);
25 a.uc_link=0;
26 a.uc_stack.ss_sp=malloc(MEM);
27 a.uc_stack.ss_size=MEM;
28 a.uc_stack.ss_flags=0;
29 makecontext(&a, (void*)&fn1, 0);
30 }
31
32 int main(int argc, char *argv[])
33 {
34 start();
35 getcontext(&Main);
36 getcontext(&T1);
37 T1.uc_link=0;
38 T1.uc_stack.ss_sp=malloc(MEM);
39 T1.uc_stack.ss_size=MEM;
40 makecontext(&T1, (void*)&fn1, 0);
41 swapcontext(&Main, &T1);
42 getcontext(&T2);
43 T2.uc_link=0;
44 T2.uc_stack.ss_sp=malloc(MEM);
45 T2.uc_stack.ss_size=MEM;
46 T2.uc_stack.ss_flags=0;
47 makecontext(&T2, (void*)&fn2, 0);
48 swapcontext(&Main, &T2);
49 printf("completed\n");
50 exit(0);
51 }