Get size of folder or file

Question

How can I retrieve size of folder or file in Java?

Answer 1

java.io.File file = new java.io.File("myfile.txt");
file.length();

This returns the length of the file in bytes or 0 if the file does not exist. There is no built-in way to get the size of a folder, you are going to have to walk the directory tree recursively (using the listFiles() method of a file object that represents a directory) and accumulate the directory size for yourself:

public static long folderSize(File directory) {
    long length = 0;
    for (File file : directory.listFiles()) {
        if (file.isFile())
            length += file.length();
        else
            length += folderSize(file);
    }
    return length;
}

WARNING: This method is not sufficiently robust for production use. directory.listFiles() may return null and cause a NullPointerException. Also, it doesn't consider symlinks and possibly has other failure modes. Use this method.

Answer 2

Using java-7 nio api, calculating the folder size can be done a lot quicker.

Here is a ready to run example that is robust and won't throw an exception. It will log directories it can't enter or had trouble traversing. Symlinks are ignored, and concurrent modification of the directory won't cause more trouble than necessary.

/**
 * Attempts to calculate the size of a file or directory.
 * 
 * <p>
 * Since the operation is non-atomic, the returned value may be inaccurate.
 * However, this method is quick and does its best.
 */
public static long size(Path path) {

    final AtomicLong size = new AtomicLong(0);

    try {
        Files.walkFileTree(path, new SimpleFileVisitor<Path>() {
            @Override
            public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) {

                size.addAndGet(attrs.size());
                return FileVisitResult.CONTINUE;
            }

            @Override
            public FileVisitResult visitFileFailed(Path file, IOException exc) {

                System.out.println("skipped: " + file + " (" + exc + ")");
                // Skip folders that can't be traversed
                return FileVisitResult.CONTINUE;
            }

            @Override
            public FileVisitResult postVisitDirectory(Path dir, IOException exc) {

                if (exc != null)
                    System.out.println("had trouble traversing: " + dir + " (" + exc + ")");
                // Ignore errors traversing a folder
                return FileVisitResult.CONTINUE;
            }
        });
    } catch (IOException e) {
        throw new AssertionError("walkFileTree will not throw IOException if the FileVisitor does not");
    }

    return size.get();
}

Answer 3

You need FileUtils#sizeOfDirectory(File) from commons-io.

Note that you will need to manually check whether the file is a directory as the method throws an exception if a non-directory is passed to it.

WARNING: This method (as of commons-io 2.4) has a bug and may throw IllegalArgumentException if the directory is concurrently modified.

Answer 4

In Java 8:

long size = Files.walk(path).mapToLong( p -> p.toFile().length() ).sum();

It would be nicer to use Files::size in the map step but it throws a checked exception.

UPDATE:
You should also be aware that this can throw an exception if some of the files/folders are not accessible. See this question and another solution using Guava.

Answer 5

public static long getFolderSize(File dir) {
    long size = 0;
    for (File file : dir.listFiles()) {
        if (file.isFile()) {
            System.out.println(file.getName() + " " + file.length());
            size += file.length();
        }
        else
            size += getFolderSize(file);
    }
    return size;
}

Answer 6

For Java 8 this is one right way to do it:

Files.walk(new File("D:/temp").toPath())
                .map(f -> f.toFile())
                .filter(f -> f.isFile())
                .mapToLong(f -> f.length()).sum()

It is important to filter out all directories, because the length method isn't guaranteed to be 0 for directories.

At least this code delivers the same size information like Windows Explorer itself does.

Answer 7

Here's the best way to get a general File's size (works for directory and non-directory):

public static long getSize(File file) {
    long size;
    if (file.isDirectory()) {
        size = 0;
        for (File child : file.listFiles()) {
            size += getSize(child);
        }
    } else {
        size = file.length();
    }
    return size;
}

Edit: Note that this is probably going to be a time-consuming operation. Don't run it on the UI thread.

Also, here (taken from https://stackoverflow.com/a/5599842/1696171) is a nice way to get a user-readable String from the long returned:

public static String getReadableSize(long size) {
    if(size <= 0) return "0";
    final String[] units = new String[] { "B", "KB", "MB", "GB", "TB" };
    int digitGroups = (int) (Math.log10(size)/Math.log10(1024));
    return new DecimalFormat("#,##0.#").format(size/Math.pow(1024, digitGroups))
            + " " + units[digitGroups];
}

Answer 8

File.length() (Javadoc).

Note that this doesn't work for directories, or is not guaranteed to work.

For a directory, what do you want? If it's the total size of all files underneath it, you can recursively walk children using File.list() and File.isDirectory() and sum their sizes.

Answer 9

The File object has a length method:

f = new File("your/file/name");
f.length();

Answer 10

If you want to use Java 8 NIO API, the following program will print the size, in bytes, of the directory it is located in.

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

public class PathSize {

    public static void main(String[] args) {
        Path path = Paths.get(".");
        long size = calculateSize(path);
        System.out.println(size);
    }

    /**
     * Returns the size, in bytes, of the specified <tt>path</tt>. If the given
     * path is a regular file, trivially its size is returned. Else the path is
     * a directory and its contents are recursively explored, returning the
     * total sum of all files within the directory.
     * <p>
     * If an I/O exception occurs, it is suppressed within this method and
     * <tt>0</tt> is returned as the size of the specified <tt>path</tt>.
     * 
     * @param path path whose size is to be returned
     * @return size of the specified path
     */
    public static long calculateSize(Path path) {
        try {
            if (Files.isRegularFile(path)) {
                return Files.size(path);
            }

            return Files.list(path).mapToLong(PathSize::calculateSize).sum();
        } catch (IOException e) {
            return 0L;
        }
    }

}

The calculateSize method is universal for Path objects, so it also works for files. Note that if a file or directory is inaccessible, in this case the returned size of the path object will be 0.

Answer 11

• Works for Android and Java
• Works for both folders and files
• Checks for null pointer everywhere where needed
• Ignores symbolic link aka shortcuts
• Production ready!

Source code:

   public long fileSize(File root) {
        if(root == null){
            return 0;
        }
        if(root.isFile()){
            return root.length();
        }
        try {
            if(isSymlink(root)){
                return 0;
            }
        } catch (IOException e) {
            e.printStackTrace();
            return 0;
        }

        long length = 0;
        File[] files = root.listFiles();
        if(files == null){
            return 0;
        }
        for (File file : files) {
            length += fileSize(file);
        }

        return length;
    }

    private static boolean isSymlink(File file) throws IOException {
        File canon;
        if (file.getParent() == null) {
            canon = file;
        } else {
            File canonDir = file.getParentFile().getCanonicalFile();
            canon = new File(canonDir, file.getName());
        }
        return !canon.getCanonicalFile().equals(canon.getAbsoluteFile());
    }

Answer 12

I've tested du -c <folderpath> and is 2x faster than nio.Files or recursion

private static long getFolderSize(File folder){
  if (folder != null && folder.exists() && folder.canRead()){
    try {
      Process p = new ProcessBuilder("du","-c",folder.getAbsolutePath()).start();
      BufferedReader r = new BufferedReader(new InputStreamReader(p.getInputStream()));
      String total = "";
      for (String line; null != (line = r.readLine());)
        total = line;
      r.close();
      p.waitFor();
      if (total.length() > 0 && total.endsWith("total"))
        return Long.parseLong(total.split("\\s+")[0]) * 1024;
    } catch (Exception ex) {
      ex.printStackTrace();
    }
  }
  return -1;
}

Answer 13

for windows, using java.io this reccursive function is useful.

    public static long folderSize(File directory) {
    long length = 0;

    if (directory.isFile())
         length += directory.length();
    else{
        for (File file : directory.listFiles()) {
             if (file.isFile())
                 length += file.length();
             else
                 length += folderSize(file);
        }
    }

    return length;
}

This is tested and working properly on my end.

Answer 14

private static long getFolderSize(Path folder) {
        try {
            return Files.walk(folder)
                      .filter(p -> p.toFile().isFile())
                      .mapToLong(p -> p.toFile().length())
                      .sum();
        } catch (IOException e) {
            e.printStackTrace();
            return 0L;
        }

Answer 15

public long folderSize (String directory)
    {
        File curDir = new File(directory);
        long length = 0;
        for(File f : curDir.listFiles())
        {
            if(f.isDirectory())
            {               
                 for ( File child : f.listFiles()) 
                 {
                     length = length + child.length();
                 }

                System.out.println("Directory: " + f.getName() + " " + length + "kb");
            }
            else
            {
                length = f.length();
                System.out.println("File: " + f.getName() + " " + length + "kb");
            }
            length = 0;
        }
        return length;
    }

Answer 16

After lot of researching and looking into different solutions proposed here at StackOverflow. I finally decided to write my own solution. My purpose is to have no-throw mechanism because I don't want to crash if the API is unable to fetch the folder size. This method is not suitable for mult-threaded scenario.

First of all I want to check for valid directories while traversing down the file system tree.

private static boolean isValidDir(File dir){
    if (dir != null && dir.exists() && dir.isDirectory()){
        return true;
    }else{
        return false;
    }
}

Second I do not want my recursive call to go into symlinks (softlinks) and include the size in total aggregate.

public static boolean isSymlink(File file) throws IOException {
    File canon;
    if (file.getParent() == null) {
        canon = file;
    } else {
        canon = new File(file.getParentFile().getCanonicalFile(),
                file.getName());
    }
    return !canon.getCanonicalFile().equals(canon.getAbsoluteFile());
}

Finally my recursion based implementation to fetch the size of the specified directory. Notice the null check for dir.listFiles(). According to javadoc there is a possibility that this method can return null.

public static long getDirSize(File dir){
    if (!isValidDir(dir))
        return 0L;
    File[] files = dir.listFiles();
    //Guard for null pointer exception on files
    if (files == null){
        return 0L;
    }else{
        long size = 0L;
        for(File file : files){
            if (file.isFile()){
                size += file.length();
            }else{
                try{
                    if (!isSymlink(file)) size += getDirSize(file);
                }catch (IOException ioe){
                    //digest exception
                }
            }
        }
        return size;
    }
}

Some cream on the cake, the API to get the size of the list Files (might be all of files and folder under root).

public static long getDirSize(List<File> files){
    long size = 0L;
    for(File file : files){
        if (file.isDirectory()){
            size += getDirSize(file);
        } else {
            size += file.length();
        }
    }
    return size;
}

Answer 17

in linux if you want to sort directories then du -hs * | sort -h

Answer 18

You can use Apache Commons IO to find the folder size easily.

If you are on maven, please add the following dependency in your pom.xml file.

<!-- https://mvnrepository.com/artifact/commons-io/commons-io -->
<dependency>
    <groupId>commons-io</groupId>
    <artifactId>commons-io</artifactId>
    <version>2.6</version>
</dependency>

If not a fan of Maven, download the following jar and add it to the class path.

https://repo1.maven.org/maven2/commons-io/commons-io/2.6/commons-io-2.6.jar

public long getFolderSize() {

    File folder = new File("src/test/resources");
    long size = FileUtils.sizeOfDirectory(folder);

    return size; // in bytes
}

To get file size via Commons IO,

File file = new File("ADD YOUR PATH TO FILE");

long fileSize = FileUtils.sizeOf(file);

System.out.println(fileSize); // bytes

It is also achievable via Google Guava

For Maven, add the following:

<!-- https://mvnrepository.com/artifact/com.google.guava/guava -->
<dependency>
    <groupId>com.google.guava</groupId>
    <artifactId>guava</artifactId>
    <version>28.1-jre</version>
</dependency>

If not using Maven, add the following to class path

https://repo1.maven.org/maven2/com/google/guava/guava/28.1-jre/guava-28.1-jre.jar

public long getFolderSizeViaGuava() {
        File folder = new File("src/test/resources");
        Iterable<File> files = Files.fileTreeTraverser()
                .breadthFirstTraversal(folder);
        long size = StreamSupport.stream(files.spliterator(), false)
                .filter(f -> f.isFile())
                .mapToLong(File::length).sum();

        return  size;
    }

To get file size,

 File file = new File("PATH TO YOUR FILE");
 long s  = file.length();
 System.out.println(s);

Answer 19

fun getSize(context: Context, uri: Uri?): Float? {
    var fileSize: String? = null
    val cursor: Cursor? = context.contentResolver
        .query(uri!!, null, null, null, null, null)
    try {
        if (cursor != null && cursor.moveToFirst()) {

            // get file size
            val sizeIndex: Int = cursor.getColumnIndex(OpenableColumns.SIZE)
            if (!cursor.isNull(sizeIndex)) {
                fileSize = cursor.getString(sizeIndex)
            }
        }
    } finally {
        cursor?.close()
    }
    return fileSize!!.toFloat() / (1024 * 1024)
}