Why is the output of this array different from the values stored in it?

Question

I have an array storing a series of numbers as follows:

static final int CodeArray[] ={
            11, 
            011,
            0011,
            1011,
            00011,
            10011,
            01011,
            000011,
            100011,
            010011,
            ...
                            }

However when I access the values(using a for loop), it returns the following:

Why is there a difference in the values being printed from the ones stored?

The ones stored are the same as the ones printed. Prefix your number with `0b` if you want binary (in Java 7). — Sotirios Delimanolis, Feb 01 '14 at 23:33
Take a look at the comment by assylias and this wiki article http://en.wikipedia.org/wiki/Octal — Timothy Randall, Feb 01 '14 at 23:54

score 4 · Accepted Answer · edited May 23 '17 at 10:25

4

Because putting a 0 before a number turns it into an octal representation, not binary.

So, for example, 011 is octal for decimal 9, which is what's printed.

See this SO question to see how to work with binary numbers in Java.

edited May 23 '17 at 10:25

Community

1
1

answered Feb 01 '14 at 23:32

AntonH

6,359
2
30
40

score 0 · Answer 2 · answered Feb 01 '14 at 23:41

0

011 is treated as octal not decimal

answered Feb 01 '14 at 23:41

Girish

1,717
1
18
30

Why is the output of this array different from the values stored in it?

2 Answers2