Intent to open Instagram user profile on Android

Question

I'm developing a social networking app and our users can connect their Instagram account to our service. I'd like to open Instagram profiles directly in their official Android app (if it is installed) but I can't find any way to do that. However, there is a page on their developer site about the exact same feature on iOS but this doesn't seem to work on Android at all. Everything I found on the web only suggests various ways to open links in a browser. Any suggestions?

Read the comments of the answer chosen as correct. It says you can't open the IG app at this point to a profile, only to a picture. The closest solution is to open the browser. — gatlingxyz, Feb 02 '14 at 15:48

score 186 · Accepted Answer · edited Jul 17 '20 at 19:43

186

I solved this problem using the following code.

Uri uri = Uri.parse("http://instagram.com/_u/xxx");
Intent likeIng = new Intent(Intent.ACTION_VIEW, uri);

likeIng.setPackage("com.instagram.android");

try {
    startActivity(likeIng);
} catch (ActivityNotFoundException e) {
    startActivity(new Intent(Intent.ACTION_VIEW, 
        Uri.parse("http://instagram.com/xxx")));
}

edited Jul 17 '20 at 19:43

juanjo

3,737
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answered May 07 '14 at 07:15

jhondge

2,352
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7

it opens browser – Aditya Vyas-Lakhan Jun 13 '17 at 05:43
4

Look at this answer: https://stackoverflow.com/questions/15497261/open-instagram-user-profile You must use ``/_u/`` format for profiles – Gonzalo Aug 22 '17 at 19:17
2

@IharobAlAsimi It's very basic Android code. Not everything needs explanation. – zundi Jan 16 '18 at 00:04

score 34 · Answer 2 · answered Sep 06 '14 at 16:23

34

Although @jhondge's solution works and is correct. This is a more cleaner way to do this:

Uri uri = Uri.parse("http://instagram.com/_u/xxx");
    Intent insta = new Intent(Intent.ACTION_VIEW, uri);
    insta.setPackage("com.instagram.android");

    if (isIntentAvailable(mContext, insta)){
        startActivity(insta);
    } else{
        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://instagram.com/xxx")));
    }

private boolean isIntentAvailable(Context ctx, Intent intent) {
    final PackageManager packageManager = ctx.getPackageManager();
    List<ResolveInfo> list = packageManager.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
    return list.size() > 0;
}

answered Sep 06 '14 at 16:23

Rahul Sainani

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I like this solution, but for some reason it does not work for me when I try to do the exact same thing for a Facebook Intent. The try/catch approach works for Facebook though, and your approach is fine for an Instagram Intent. Do you by chance know what could cause this? – Krøllebølle Feb 05 '16 at 17:16
@Krøllebølle I think I faced the same issue and switched to try catch for facebook. Don't know what causes this. – Rahul Sainani Feb 09 '16 at 16:51
This works for me... I Tried it in Android Emulator without Instagram app it opened in the browser and I tried it in my Mobile in which Instagram is installed and it opened the Instagram app. Thank You. – Ramesh Aug 16 '19 at 21:24

score 12 · Answer 3 · answered Jun 04 '15 at 13:37

To open directly instagram app to a user profile :

String scheme = "http://instagram.com/_u/USER";
String path = "https://instagram.com/USER";
String nomPackageInfo ="com.instagram.android";
    try {
        activite.getPackageManager().getPackageInfo(nomPackageInfo, 0);
        intentAiguilleur = new Intent(Intent.ACTION_VIEW, Uri.parse(scheme));
        } catch (Exception e) {
            intentAiguilleur = new Intent(Intent.ACTION_VIEW, Uri.parse(path));
        }
        activite.startActivity(intentAiguilleur); 

// Use this link to open directly a picture
  String scheme = "http://instagram.com/_p/PICTURE";

it opens in browser – Aditya Vyas-Lakhan Jun 13 '17 at 05:33 — Aditya Vyas-Lakhan, Jun 13 '17 at 05:33

score 4 · Answer 4 · answered Jun 13 '17 at 05:56

I tried this way and it worked for me..

instabtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {


                Intent instaintent = getActivity().getPackageManager().getLaunchIntentForPackage("com.instagram.android");

                instaintent.setComponent(new ComponentName( "com.instagram.android", "com.instagram.android.activity.UrlHandlerActivity"));
                instaintent.setData( Uri.parse( "https://www.instagram.com/_u/bitter_truth_lol") );

                startActivity(instaintent);

            }
        });

score 4 · Answer 5 · answered Apr 03 '21 at 08:31

Based on @alex-karapanos answer, I use this code:

fun launchInsta() {
    val uriForApp: Uri = Uri.parse("http://instagram.com/_u/xxx")
    val forApp = Intent(Intent.ACTION_VIEW, uriForApp)

    val uriForBrowser: Uri = Uri.parse("http://instagram.com/xxx")
    val forBrowser = Intent(Intent.ACTION_VIEW, uriForBrowser)

    forApp.component =
        ComponentName(
            "com.instagram.android",
            "com.instagram.android.activity.UrlHandlerActivity"
        )

    try {
        startActivity(forApp)
    } catch (e: ActivityNotFoundException) {
        startActivity(forBrowser)
    }
}

score 2 · Answer 6 · answered Mar 06 '20 at 22:21

Kotlin Version of @jhondge answer:

            val uriForApp: Uri = Uri.parse("http://instagram.com/_u/xxx")
            val forApp = Intent(Intent.ACTION_VIEW, uriForApp)

            val uriForBrowser: Uri = Uri.parse("http://instagram.com/xxx")
            val forBrowser = Intent(Intent.ACTION_VIEW, uriForBrowser)

            forApp("com.instagram.android")

            try {
                startActivity(context, forApp, null)

            } catch (e: ActivityNotFoundException) {
                startActivity(context, forBrowser, null)

            }

score 1 · Answer 7 · edited Dec 20 '18 at 02:03

I implemented this using fragment in webview but I have one issue, the instagram pop up comes three times :

webView.setWebViewClient(new WebViewClient()
        {
 public boolean shouldOverrideUrlLoading(WebView viewx, String urlx)
            {
 if(Uri.parse(urlx).getHost().endsWith("instagram.com")) {

                    gotoinstagram();

                  return false;
                }

                Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(urlx));
                viewx.getContext().startActivity(intent);
                return true;
            }



        });

outside of onCreateView

//instagram

public void gotoinstagram()
{

    Uri uri = Uri.parse("http://instagram.com/_u/XXXX");
    Intent likeIng = new Intent(Intent.ACTION_VIEW, uri);

    likeIng.setPackage("com.instagram.android");

    try {
        startActivity(likeIng);
    } catch (ActivityNotFoundException e) {
        startActivity(new Intent(Intent.ACTION_VIEW,
                Uri.parse("http://instagram.com/XXXX")));
    }

}

score 1 · Answer 8 · answered Oct 03 '21 at 05:38

A number of people already answered this question but still I am answering. Using the method answered above the workflow is go through 3 steps.

Step1: The app parse uri and intent

Step2: The intent go to browser and load Instagram url

Step3: Browser then redirect to Instagram App

But to open Instagram app directly without going to Browser you can use the method mentioned below. Create an Intent method like below:-

private Intent instaIntn(Context context) {
Intent i1;
String instaId = "your insta id";
String appResolver = "instagram://user?username=";
String webResolver = "https://instagram.com/";
String instaPackageName = "com.instagram.android";
String instaLitePackName = "com.instagram.lite";

try {
context.getPackageManager().getPackageInfo(instaPackageName, 0);
i1 = new Intent(Intent.ACTION_VIEW, Uri.parse(appResolver+instaId));
} catch (PackageManager.NameNotFoundException e1) {
Toast.makeText(getApplication(), "Instagram not found", Toast.LENGTH_SHORT).show();
try {
context.getPackageManager().getPackageInfo(instaLitePackName, 0);
i1 = new Intent(Intent.ACTION_VIEW, Uri.parse(appResolver+instaId));
} catch (PackageManager.NameNotFoundException e2) {
Toast.makeText(getApplication(), "Instagram and instagram lite not found", Toast.LENGTH_SHORT).show();
i1 = new Intent(Intent.ACTION_VIEW, Uri.parse(webResolver+instaId));
}
}
return i1;
}

Now you can Start this intent from anywhere inside class by simply calling below statement:-

startActivity(instaIntn(getApplicationContext()));

Now what it will do, it will try to open Instagram app, if instagram app is not installed then it will try to open Instagram lite. If both app is missing then it will intent to browser. The above method intent user to Instagram app and user profile. You can also intent user to Instagram image video and other page. See full documentation in here https://developers.facebook.com/docs/instagram/sharing-to-feed/

Intent to open Instagram user profile on Android

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