You can take into account which of the data are important for you: cols (number of columns), rows (number of columns), data (which contains the pixel information), type (data type and channel number).
You have to vectorize your matrix, because it is not neccessarrily continuous and take into account the variations of the size of a pixel in the memory.
Suppose:
cv::Mat m;
Then to allocate:
int depth; // measured in bytes
switch (m.depth())
{
// ... you might check for all of the possibilities
case CV_16U:
depth = 2;
}
char *array = new char[4 + 4 + 4 + m.cols * m.rows * m.channels() * depth]; // rows + cols + type + data
And than write the header information:
int *rows = array;
int *cols = &array[4];
int *type = &array[8];
*rows = m.rows;
*cols = m.cols;
*type = m.type;
And finally the data:
char *mPtr;
for (int i = 0; i < m.rows; i++)
{
mPtr = m.ptr<char>(i); // data type doesn't matter
for (int j = 0; j < m.cols; j++)
{
array[i * rows + j + 3 * 4] = mPtr[j];
}
}
Hopefully no bugs in the code.