Separated CIN input with NO separators

Question

So, the question is as follows: I have an input data, loaded into cin, which (data) has no separators at all and consists of 2-dig. hex numbers, for ex:

ab2b6f //here it is ab 2b 6f

Is it possible to separate them without buffering? I do not want to waste a memory, 'cause inputs can be really long;

UPD: solved by using 2-char buffer.

===================================

cin::get or cin::read? you can have a 2 chars buffer and read into it in a loop. so you will waste(?) only 2 bytes. — Hayri Uğur Koltuk, Feb 06 '14 at 08:57
@HayriUğurKoltuk, then manually convert chars into decimal ints? I do not need a hex value, a need a _decimal_ representation of each number in stream. — doctor_mee, Feb 06 '14 at 10:20

score 0 · Accepted Answer · edited May 23 '17 at 10:31

0

You may set an input buffer as described here: How to get IOStream to perform better? and then istream::read(...) an exact number of bytes from the stream.

edited May 23 '17 at 10:31

Community

1
1

answered Feb 06 '14 at 08:59

user3159253

16,836
3
30
56

Separated CIN input with NO separators

1 Answers1