is this code still supported on php version 5.4.24

Question

When my server updated to PHP version 5.4.24, I've encountered some errors on my script using this code

.=

sample code are

$test .= 'hello';
$test .= 'to';
$test .= 'all';
echo $test;

I got undefined variable test. Everything is working when my server PHP version is 5.2.10

Is .= still supported on PHP version 5.4.24

Is there any alternative code for this? Or how can I fix this?

You would get `undefined variable test` on your 5.2.10 PHP as well, it's just that you were either not reporting errors, or not displaying them. If `error_reporting` was turned up to `E_ALL`, you would've gotten the error there too. Initialize it with `$test = ''` before appending to it with `.=`. — Michael Berkowski, Feb 06 '14 at 19:32
possible duplicate of [PHP: "Notice: Undefined variable" and "Notice: Undefined index"](http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index) — Michael Berkowski, Feb 06 '14 at 19:33
Always when developing code, on any PHP version, make sure `error_reporting` is turned all the way up and you are using `display_errors` to show them on screen as you code. Fix _all_ of them, including notices and warnings. Set those in php.ini or at runtime with `error_reporting(E_ALL); ini_set('display_errors', 1);` — Michael Berkowski, Feb 06 '14 at 19:35
@MichaelBerkowski If only WordPress plug-in authors would do this, it would make the times I work in WordPress for clients so much less painful. — Matt, Feb 06 '14 at 20:10

score 1 · Answer 1 · answered Feb 06 '14 at 19:34

1

I think this is what you would need to do. Just use = the first time.

$test = 'hello';
$test .= 'to';
$test .= 'all';
echo $test;

answered Feb 06 '14 at 19:34

Dominick

score 0 · Accepted Answer · edited May 23 '17 at 12:21

0

If you do

$test='';
$test .= 'hello';
$test .= 'to';
$test .= 'all';
echo $test;

It should solve your problem.

edited May 23 '17 at 12:21

Community

answered Feb 06 '14 at 19:34

TecBrat

thanks tecbrat this solved my problem, i thought it was version of php. – user3281071 Feb 07 '14 at 02:56

2 Answers2