How to read a string of characters and store into multiple variables?

Question

If I prompt the user to enter 6 numbers in one line, for example:

3 4 5 6 7 8

How can I store the first number in the string into variable Num1, 2nd number into variable Num2, 3rd number into variable Num3, etc.? I.e., I need to prompt the user to input a single line containing 6 different numbers, and then split those 6 numbers into 6 different variables.

This is my code:

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string num;
    cout << "Enter one line containing 6 integers" << endl; 
    getline(cin, num)

    return 0;
}

Not sure if string is the right type to use.

And this method causes all 6 numbers to be stored into num instead of splitting the 6 numbers up into separate variables.

That's what arrays are for... It's not practical to use so many variables. — Maria Ines Parnisari, Feb 07 '14 at 04:01
You already got answered in your last topic: http://stackoverflow.com/questions/21614999/how-to-read-a-single-line-of-numbers-into-different-variables — Paweł Stawarz, Feb 07 '14 at 04:05
You should never say `2` or `3` in your code. Magic numbers mean you're violating the zero-one-many rule. — Kerrek SB, Feb 07 '14 at 04:05

score 0 · Accepted Answer · answered Feb 07 '14 at 04:02

0

You can do like:

cin>>num1>>num2>>num3>>num4>>num5>>num6;

c++ breaks string on space characters.

Use 'cin' in place of 'getline'.

answered Feb 07 '14 at 04:02

Swapnil R Mehta

117
1
12

score 0 · Answer 2 · edited May 23 '17 at 11:59

0

In C you can use split strings with strtok.

See this tutorial: http://www.c-howto.de/tutorial-strings-zeichenketten-stringfunktionen-zerteilen-strtok.html

For C++ we have already a question that might answer your needs: Split a string in C++?

Hope this helps you.

edited May 23 '17 at 11:59

Community

1
1

answered Feb 07 '14 at 04:04

GreatSUN

50
3

score 0 · Answer 3 · answered Feb 07 '14 at 04:14

You can do what you are asking like this

std::string line;
std::getline(std::cin, line);
std::istringstream iss(line);
iss >> num1 >> num2 >> num3 >> num4 >> num5 >> num6;

However, I would highly encourage you to look into a container (e.g. std::array, std::vector, std::list);

How to read a string of characters and store into multiple variables?

3 Answers3