2

I'm running this code:

findall(A, syllable(A), X), nth1(1001,X,B).

syllable returns a valid syllable as a list of sounds. i.e. [e,g,g,s]. I just want to know the 1001st possible syllable, B = [θ,i,p]. And I get that printed to the screen. But after B is shown, prolog shows all of X. Which is approximately 40000 different syllables. This is too much information for me.

How can I hide X from being shown or just have B shown?

Appreciate your help!

GuavaKhan
  • 187
  • 1
  • 9

1 Answers1

1

make a 'projection': 

sy(B) :- findall(A, syllable(A), X), nth1(1001,X,B).

or better, instead of building a full list just to peek one element, define call_nth/2 and then 'jump to' the right solution

?- call_nth(syllable(B), 1001).
Community
  • 1
  • 1
CapelliC
  • 59,646
  • 5
  • 47
  • 90